我想从表中匹配状态'的所有记录中选择as'打开',然后执行与另一个表的左连接。我试过这个,但它不起作用:
SELECT (ticket.* WHERE ticket.status = 'Open'), ticketupdate.updatetime
FROM ticket
INNER JOIN ticketupdate ON ticketupdate.ticketid = ticket.ticketid
答案 0 :(得分:2)
很简单,您可以使用where
子句
select tk.*, tu.updatetime
from ticket tk
left join ticketupdate tu on tu.ticketid = tk.ticketid
where tk.status = 'Open';
答案 1 :(得分:0)
您可以放入嵌套的SELECT
SELECT ticket.* , ticketupdate.updatetime
FROM (SELECT * FROM ticket WHERE status = 'Open') AS ticket
LEFT JOIN ticketupdate
ON ticketupdate.ticketid = ticket.ticketid