Question

您好我在如何通过使用角色来防止会员获得其他会员头像，因为您可以看到具有私人头像角色的会员将保护他们的头像。这就是我在.py

中对此进行编码的方式

class Avatar:
    """Returns members avatar."""

    def __init__(self, bot):
        self.bot = bot

    @commands.command(pass_context=True)
    @commands.cooldown(5, 60, commands.BucketType.user)
    async def avatar(self, context, member: discord.Member):
        """Returns members avatar."""

        role = discord.utils.get(member.server.roles, name="Private Avatar")
        author = context.message.author.mention
        mention = member.mention

        if role in member.roles:
            pa = "This members avatar is private"
            await self.bot.say(pa)
            return

        avatar = "{0} here is {1}'s avatar"

        u = member.avatar_url
        url = process_avatar(u)
        embed = discord.Embed(description=avatar.format(author, mention), colour=discord.Colour.blue())
        embed.set_image(url=u)
        await self.bot.say(embed=embed)

我挣扎的代码行是这一行

 if role in member.roles:
            pa = "This members avatar is private"
            await self.bot.say(pa)
            return

这基本上应该输出消息＆＃34;这个成员头像是私有的＆＃34;没有检索头像但它仍然检索带有消息的头像。

非常感谢您的帮助。

Answer 1

你过度复杂了。只需使用else:，就像这样：

class Avatar:
    """Returns members avatar."""

    def __init__(self, bot):
        self.bot = bot

    @commands.command(pass_context=True)
    @commands.cooldown(5, 60, commands.BucketType.user)
    async def avatar(self, context, member: discord.Member):
        """Returns members avatar."""
        
        role = discord.utils.get(member.server.roles, name="Private Avatar")
        author = context.message.author.mention
        mention = member.mention
        
        if role in member.roles:
            pa = "This members avatar is private"
            await self.bot.say(pa)
        else:
		
            avatar = "{0} here is {1}'s avatar"

            u = member.avatar_url
            url = process_avatar(u)
            embed = discord.Embed(description=avatar.format(author, mention), colour=discord.Colour.blue())
            embed.set_image(url=u)
            await self.bot.say(embed=embed)

P.S。：理论上，您的代码应该有效。除非有一些我没有看错的事，那就是。我还必须注意，仅仅因为机器人不会获取它，并不意味着客户端不能。头像是公开的。

私有化身discord.py

1 个答案: