Question

我将数据发送到数据库时遇到问题。

错误：

E / SQLiteDatabase：插入linka = 14时出错jedu = false cas = 2018-05-03   17:33:05 id_veh = 1234                     android.database.sqlite.SQLiteException：table m_register没有名为linka（code 1）的列:,编译时：   INSERT INTO m_register（linka，jedu，cas，id_veh）VALUES（？，？，？，？）

这是我的类，其中addData被调用。 addData方法

引发了错误

      package com.example.pc.mhdapp;

import android.content.ContentValues;
import android.content.Context;
import android.database.sqlite.SQLiteDatabase;
import android.database.sqlite.SQLiteOpenHelper;

import android.util.Log;

public class DatabaseHelper extends SQLiteOpenHelper{
    private static final String TAG = "DatabaseHelper";
    private static final String TABLE_NAME = "m_register";
    private static final String COL1 = "ID";
    private static final String COL2 = "id_veh";
    private static final String COL3 = "linka";
    private static final String COL4 = "jedu";
    private static final String COL5 = "cas";
    public DatabaseHelper(Context context){
    super(context, TABLE_NAME, null, 1);

}
@Override
public void onCreate(SQLiteDatabase db) {
String createTable = "CREATE TABLE " + TABLE_NAME + "  (ID INTEGER(11) PRIMARY KEY AUTOINCREMENT," +
        COL2 + " VARCHAR(11)," +
        COL3 + " VARCHAR(50)," +
        COL4 + " VARCHAR(3)," +
        COL5 + " DATETIME)";
db.execSQL(createTable);
}

@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
    db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME);
    onCreate(db);
}

public boolean addData(String id_vehl, String linkas, String jedus, String cass){
    SQLiteDatabase db = this.getWritableDatabase();
    ContentValues contentValues = new ContentValues();
    contentValues.put(COL2,  id_vehl);
    contentValues.put(COL3,  linkas);
    contentValues.put(COL4,  jedus);
    contentValues.put(COL5,  cass);

    Log.d(TAG, "addDATA: adding " +  id_vehl+ ", "+linkas+ ", "+jedus+ ", "+cass+ " to " + TABLE_NAME);
    long result = db.insert(TABLE_NAME,null, contentValues);
    if(result == -1){
        return false;
    }else{
        return true;
    }
}

}

Answer 1

似乎您通过添加其他列来更改数据库架构，尝试卸载并重新安装应用程序，它将起作用。提示：下次修改数据库模式时，请升级onUpgrade中的版本

表x没有名为y的列

1 个答案: