Question

我的问题与Is it possible to have a relation where the foreign key is also the primary key?类似，但我必须使用Fluent API执行此操作。

我基本上和问题中描述的情况相同，但由于我们的编码标准，我无法在我的域模型上使用注释。这是一些代码（澄清）：

域类：

public class Table1
{
    public long ID { get; set; }
    public int SubTableType { get; set; }
    ...

    public Table2 Table2 { get; set; }
    public Table3 Table3 { get; set; }
    public List<Table4> Table4s { get; set; }
    public List<Table5> Table5s { get; set; }
}

public class Table2
{
    public long ID { get; set; }
    public string Location { get; set; }
    public string Task { get; set; }
    ...

    public Table1 Table1 { get; set; }
    public Table6 Table6 { get; set; }
    public List<Table7> Table7s { get; set; }
}

public class Table3
{
    public long ID { get; set; }
    public string DescriptionAndLocation { get; set; }
    ...

    public Table1 Table1 { get; set; }
}

配置类：

internal class Table1Configuration : EntityTypeConfiguration<Table1>
{
    public Table1Configuration()
    {
        ToTable("Table1");

        HasKey(so => so.ID);

        Property(so => so.SubTableType)
            .IsRequired();
        Property(so => so.ID)
            .IsRequired()
            .HasDatabaseGeneratedOption(System.ComponentModel.DataAnnotations.Schema.DatabaseGeneratedOption.Identity);
        ...
    }
}

internal class Table2Configuration : EntityTypeConfiguration<Table2>
{
    public Table2Configuration()
    {
        ToTable("Table2");

        HasKey(bc => bc.ID);

        Property(bc => bc.ID)
            .IsRequired();
        Property(bc => bc.Location)
            .IsOptional()
            .HasColumnType("nvarchar")
            .HasMaxLength(50);
        Property(bc => bc.Task)
            .IsOptional()
            .HasColumnType("nvarchar")
            .HasMaxLength(4000);
        ...

        HasRequired(bc => bc.Table1)
            .WithOptional(so => so.Table2);
        HasRequired(bc => bc.Table8)
            .WithMany(bot => bot.Table2s)
            .HasForeignKey(bc => bc.Tabe8ID);
    }
}

internal class Table3Configuration : EntityTypeConfiguration<Table3>
{
    public Table3Configuration()
    {
        ToTable("Table3");

        HasKey(hic => hic.ID);

        Property(hic => hic.DescriptionAndLocation)
            .IsOptional()
            .HasColumnType("nvarchar")
            .HasMaxLength(4000);
        Property(hic => hic.ID)
            .IsRequired()
            .HasDatabaseGeneratedOption(System.ComponentModel.DataAnnotations.Schema.DatabaseGeneratedOption.Identity);

        HasRequired(hic => hic.Table1)
            .WithOptional(so => so.Table3);
    }
}

当我运行此代码时，我收到错误：

Invalid column name 'Table2_ID'.

Answer 1

我会尝试这样的事情：

$(function() {

    var $sidebar   = $("#sidebar"), 
        $window    = $(window),
        offset     = $sidebar.offset(),
        topPadding = 75;
      var _docHeight = (document.height !== undefined) ? document.height : document.body.offsetHeight;



      var footer_top = $("#footer").offset().top;
      var div_top = $('#sticky-anchor').offset().top;
      var div_height = $("#sidebar").height();

      var desiredHeight = _docHeight - footer_top;

    $window.scroll(function()
    {
        if ($window.scrollTop() > offset.top)
        {
            $sidebar.stop().animate({
                marginTop: $window.scrollTop() - offset.top + topPadding
            });
        }

        else if($window.scrollTop > desiredHeight)
        {
            $sidebar.stop().animate({
                marginTop: $window.scrollTop()-100
            });
        }
        else {
            $sidebar.stop().animate({
                marginTop: 0
            });
        }
    });

});

Answer 2

你所问的是所谓的Shared Primary Key Associations，它是一对一关系的标准（并且得到更好支持的）EF6模型。

您应该删除用于定义影子FK属性（您不需要）的ID调用，而不是删除MapKey属性。

由于按惯例名为ID的属性是PK并且是必需的，基本上所有你需要的是：

HasRequired(hic => hic.Table1)
    .WithOptional(so => so.Table2); // or Table3

或明确相当于[Key] / [ForeignKey]组合：

HasKey(hic => hic.ID);

HasRequired(hic => hic.Table1)
    .WithOptional(so => so.Table2); // or Table3

正好是文档中Configuring a Required-to-Optional Relationship (One-to–Zero-or-One)的示例。

如何定义一个域模型，其中主键也是具有流畅api的外键

2 个答案: