我正在尝试理解同事编写的SQL,我很难理解GROUPING()函数在这种情况下是如何工作的。为什么 date_level_year_quarter_month 的值在最后两行中等于3和7?先感谢您!
SELECT
t_year,
t_quarter,
t_month,
GROUPING(t_year, t_quarter, t_month) date_level_year_quarter_month
FROM
d_time
WHERE t_year IN (2016)
GROUP BY
ROLLUP(t_year, t_quarter, t_month)
ORDER BY 1, 2, 3;
+---------+------------+------------+-------------------------------+
| t_year | t_quarter | t_month | date_level_year_quarter_month |
+---------+------------+------------+-------------------------------+
| 2016 | 1 | 1 | 0 |
+---------+------------+------------+-------------------------------+
| 2016 | 1 | 2 | 0 |
+---------+------------+------------+-------------------------------+
| 2016 | 1 | 3 | 0 |
+---------+------------+------------+-------------------------------+
| 2016 | 1 | | 1 |
+---------+------------+------------+-------------------------------+
| 2016 | ... | ... | ... |
+---------+------------+------------+-------------------------------+
| 2016 | | | 3 |
+---------+------------+------------+-------------------------------+
| | | | 7 |
+---------+------------+------------+-------------------------------+
编辑: 看起来对于每个'添加'维度,GROUPING函数的值是'previous grouping'+ 1的值的两倍,但是我仍然不清楚函数如何首先计算这个值。
SELECT
T_YEAR
, T_QUARTAL
, T_MONTH
, T_WEEK
, T_DATE
, GROUPING (T_YEAR ) AS LEVEL_YEAR
, GROUPING (T_YEAR, T_QUARTER) AS LEVEL_YEAR_QUARTAL
, GROUPING (T_YEAR, T_QUARTER, T_MONTH) AS LEVEL_YEAR_QUARTAL_MONTH
, GROUPING (T_YEAR, T_QUARTER, T_MONTH, T_WEEK) AS LEVEL_YEAR_QUARTAL_MONTH_WEEK
, GROUPING (T_YEAR, T_QUARTER, T_MONTH, T_WEEK, T_DAY) AS LEVEL_YEAR_QUARTAL_MONTH_WEEK_DAY
FROM D_TIME
WHERE T_YEAR=2016 AND T_WEEK = 1
GROUP BY
ROLLUP (T_YEAR, T_QUARTER, T_MONTH, T_WEEK, T_DAY)
ORDER BY 5,1,2,3,4;
答案 0 :(得分:0)
我在Exasol documentation找到了答案。
“在多个参数的情况下,结果值是一个二进制表示类似于
的数字GROUPING(arg1), GROUPING(arg2),..., GROUPING(argn).
E.g。以下是真的:
GROUPING(a,b,c) = 4xGROUPING(a) + 2xGROUPING(b) + 1xGROUPING(c)."