Question

根据选定的DataTables行创建数组

$('#savenlp').click(recordjourney);

function recordjourney() {
var data = table.rows(['.selected']).data().toArray();
console.log( (data) );
console.log( JSON.stringify(data) );
}

data返回

0 : (8) ["Which", "TitleCase", "QuestionWord", "", "", "", "", ""]

JSON.stringify(data)返回

[["baseball","Noun","Singular","","","","",""]]

此信息是动态生成的，所以我只想取第一个值（在本例中为baseball）并将其转换为类似

的内容

  "baseball": [
    "Noun",
    "Singular"
  ]

我可以返回第一个值（我想要使用的键）

alert(data[0][0]);

我在PHP方面更擅长，但我越来越多地学习javascript / jquery。

这是我的理解javascript没有关联数组，所以我对如何生成它有点困惑。

Answer 1

const data = [
  ["baseball","Noun","Singular","","","","",""],
  ["baseballs","Noun","","Plural","","","","",]
];
const mappedData = data.reduce((acc, row) => { acc[row.shift()] = row.filter(d => d !== ''); return acc; }, {});
console.log(mappedData);

Answer 2

我们可以使用对象解构和扩展运算符以方便使用。在下面的示例中，key将是第一个项目，所有其余项目将放在newData变量中

const data = [["baseball","Noun","Singular","","","","",""]];
const [key, ...newData] = data[0]
// if you want the new data to not have empty entries, simple apply the filter
const newDataFiltered = newData.filter(item => !!item)
const objWithEmpty = {[key]: newData}
const objWithoutEmpty = {[key]: newDataFiltered}


console.log(objWithEmpty, objWithoutEmpty)

对于外部数组中的多个数组，只需将整个逻辑包含在for循环中

const data = [
  ["baseball","Noun","Singular","","","","",""],
  ["baseball1","Noun1","Singular1","","","","",""],
  ["baseball2","Noun2","Singular2","","","","",""]
];
const objWithEmpty = {}
const objWithoutEmpty = {}

data.forEach((array) => {
  const [key, ...newData] = array
  // if you want the new data to not have empty entries, simple apply the filter
  const newDataFiltered = newData.filter(item => !!item)
  objWithEmpty[key] = newData
  objWithoutEmpty[key] = newDataFiltered
})

console.log(objWithEmpty, objWithoutEmpty)

Answer 3

只需从{ "rules": { "camelcase": [2, {"properties": "never"}] } }中提取所需的值，然后将它们放入您喜欢的格式化对象中：

data

但是拥有一个只有一个属性的对象真是太奇怪了。如果您的const data = [["baseball","Noun","Singular","","","","",""]]; const firstArr = data[0]; const transformedFirstObject = { [firstArr[0]]: [firstArr[1], firstArr[2]], }; console.log(transformedFirstObject);中可能包含多个子数组，并且您希望将数组数组转换为对象数组，请使用data：

map

Answer 4

与其他答案相比有点简单，但同样有效。

const data = [
  ["baseball","Noun","Singular","","","","",""],
  ["baseball1","Noun1","Singular1","","","","",""],
  ["baseball2","Noun2","Singular2","","","","",""]
];

const obj = [];
data.forEach(function(i) {
  let jsonObj = {};
  jsonObj [i[0]] = i.slice(1).filter(x=>x !='');
  obj.push(jsonObj)
});

console.log(JSON.stringify(obj))

Answer 5

考虑多个数组元素，只需使用forEach。

＆＃13;

var obj = {};
var arr = [
  ["baseball", "Noun", "Singular", "", "", "", "", ""],
  ["Test", "Test1", "Test2", "", "", "", "", ""]
];

arr.forEach(function(val, idx) {
  val.forEach(function(val1, idx1) {
    if (idx1 === 0) {
      obj[val1] = val.slice(1, val.length)
    }
  })
})
console.log(JSON.stringify(obj))

＆＃13;

将第一个值设置为Javascript数组中的键

5 个答案: