Question

我有一个函数在我的Django应用程序中处理csvs的zip文件。我通过创建新线程并将该函数作为run方法发送来渲染视图时按下按钮后调用该函数。这是我想要调用的函数：

update_db.py

max_allowed_packet

问题是如果我在视图中调用它，该函数运行完全正常，但如果我尝试将它传递给线程则不会。这就是我在调用环境中所拥有的：

def upload_files(csv_files):
    conn = sqlite3.connect('/path/to/db.db')
    c = conn.cursor()

    for csv_filename in csv_files.namelist():
        if csv_filename.endswith('.csv'):
            csv_file = csv_files.open(csv_filename)

            # extract team name from csv_file string, remove whitespace
            table_name = csv_filename.rsplit('/',2)[1]
            table_name = re.sub('[^\w+]', '', table_name)

            try:
                df = pandas.read_csv(csv_file, error_bad_lines=False)
                df.to_sql(table_name, conn, if_exists='append', index=False)

                ##do some stuff

            except pandas.errors.EmptyDataError as ex:
                print(str(csv_file) + ' was empty; continuing...')
                continue;

    conn.commit()
    conn.close()

这是堆栈跟踪：

def upload(request):
    if request.method == 'POST' and request.FILES['myfile']:
        myfile = request.FILES['myfile']
        if str(myfile.name).endswith('.zip'):

            unzipped = zipfile.ZipFile(myfile)
            # If I uncomment this line, it doesn't throw an error
            #upload_files(unzipped)


            # When these lines execute, I get an error
            t = threading.Thread(target = upload_files, args = (unzipped, ))
            t.daemon = True
            t.start()

            return render(request, 'webapp/upload.html', {
                'success': True
            })
    return render(request, 'webapp/upload.html', {
        'success': False
    })

为什么在单独的线程中运行该函数会导致错误，解决问题的最佳方法是什么？

在单独的线程中执行时的ValueError

0 个答案: