如果某个表格显示特定日期的广告资源中各个项目的值,那么如何返回反映每个唯一日期的总价值的摘要数据?
例如,给定以下结构:
DECLARE @INVENTORY TABLE(
EFFECTIVE_DATE DATE NOT NULL,
ITEM INT NOT NULL,
VALUE DECIMAL(6,2) NOT NULL
)
INSERT @INVENTORY VALUES ('2011-01-01', 1, 40.01)
INSERT @INVENTORY VALUES ('2011-01-01', 2, 35.01)
INSERT @INVENTORY VALUES ('2011-01-01', 3, 17.01)
INSERT @INVENTORY VALUES ('2011-02-01', 2, 50.01)
INSERT @INVENTORY VALUES ('2011-02-01', 3, 45.01)
INSERT @INVENTORY VALUES ('2011-03-01', 1, 10.01)
INSERT @INVENTORY VALUES ('2011-03-01', 4, 5.01)
可以使用什么查询来产生以下内容?
EFFECTIVE_DATE TOTAL_VALUE
2011-01-01 92.03
2011-02-01 135.03
2011-03-01 110.04
挑战在于库存价值将继续进入后续日期。请注意,2011-03-01表示所有四个不同项目的最新值的总和,尽管其中只有两个具有当天的记录。
答案 0 :(得分:2)
这显示每个日期的项目值:
SELECT
D.EFFECTIVE_DATE,
I.ITEM,
COALESCE((SELECT TOP 1 VALUE FROM @INVENTORY II WHERE (II.ITEM = I.ITEM) AND (II.EFFECTIVE_DATE <= D.EFFECTIVE_DATE) ORDER BY EFFECTIVE_DATE DESC),0) VALUE
FROM (SELECT DISTINCT EFFECTIVE_DATE FROM @INVENTORY) D
CROSS JOIN (SELECT DISTINCT ITEM FROM @INVENTORY) I
这显示摘要:
SELECT
EFFECTIVE_DATE,
SUM(VALUE)
FROM
(
SELECT
D.EFFECTIVE_DATE,
I.ITEM,
COALESCE((SELECT TOP 1 VALUE FROM @INVENTORY II WHERE (II.ITEM = I.ITEM) AND (II.EFFECTIVE_DATE <= D.EFFECTIVE_DATE) ORDER BY EFFECTIVE_DATE DESC),0) VALUE
FROM (SELECT DISTINCT EFFECTIVE_DATE FROM @INVENTORY) D
CROSS JOIN (SELECT DISTINCT ITEM FROM @INVENTORY) I
) GROUPED_VALUES
GROUP BY EFFECTIVE_DATE
答案 1 :(得分:0)
SELECT EFFECTIVE_DATE, SUM(VALUE) AS TOTAL_VALUE
FROM @INVENTORY
GROUP BY EFFECTIVE_DATE
答案 2 :(得分:0)
尝试此查询。它首先选择每个项目的最大日期,然后将其与原始表格连接以获得总值。
;WITH Items as
(
select Item,MAX(EFFECTIVE_DATE) Med
from @INVENTORY
group by Item
)
select sum(Value)
from Items a inner join
@INVENTORY b on a.Item=b.Item and a.Med=b.EFFECTIVE_DATE