Question

我正在学习TypeScript并玩弄猫鼬。我有以下架构定义（简化形式）：

interface IContact extends Document {
  type: string;
  firstName?: string;
}

const contactSchema = new mongoose.Schema({
  contactType: {
    type: String,
    required: true,
    trim: true,
    enum: ['person', 'general']
  },
  firstName: {
    type: String,
    required: function() {
      return this.contactType === 'person';
    },
    minlength: 1,
    trim: true
  }})

 const Contact = mongoose.model<IContact>('Contact', contactSchema);

现在，TypeScript编译器给出了以下错误：

属性'contactType'在类型'Schema |上不存在SchemaType | SchemaTypeOpts'。属性'contactType'在'Schema'类型上不存在。

以这种方式验证必填字段，取自mongoose文档，正确（使用this关键字），还是有其他方式？或者，我应该以某种方式注释我的架构，TypeScript会知道我的架构上存在contactType属性吗？

Answer 1

您可以尝试一下，这对我有用：

SELECT max(t1.id) as id, t1.firstName, t1.lastName, adr.address, cty.City 
FROM test t1
cross apply (select top(1) address from test t2 
             where t1.FirstName = t2.FirstName and 
                   t1.LastName = t2.LastName and
                   t2.address is not null
             order by id desc) adr(Address)
cross apply (select top(1) city from test t2 
             where t1.FirstName = t2.FirstName and 
                   t1.LastName = t2.LastName and
                   t2.city is not null
             order by id desc) cty(City)
group by t1.firstName, t1.lastName, adr.address, cty.City;

Answer 2

您也可以做类似的事情

required: function() {
  return ((this as unknown) as IContact).contactType === 'person';
}

或者只是

required: function() {
  return (this as any).contactType === 'person';
}

在第二种情况下，使用TypeScript的含义有点丢失，但是在这种情况下，它似乎并不那么重要

使用Typescript进行Mongoose Schema属性验证

2 个答案: