Question

我有一大堆XML数据需要使用XMLTable来获取bulletinWorkl:id和bulletinWork/outOfServices/outOfService/document:destinationName。

<?xml version="1.0" encoding="ISO-8859-1"?>
<cern:bulletinWork id="5307cedc-2208-3701-9b9d-e69664b1ef31">
  <cern:outOfServices>
    <cern:outOfService id="e95d491b-2876-3e08-901f-b0f79be86bfb">
      <cern:document destinationName="MonsA" type="S427"></cern:document>
    </cern:outOfService>
    <cern:outOfService id="fab04992-a33f-3a8c-ad16-29cd54fb93d6">
      <cern:document destinationName="MonsB" type="S427"></cern:document>
    </cern:outOfService>
  </cern:outOfServices>
</cern:bulletinWork>

我正在尝试运行此查询，并成功取回bulletinWork中的ID属性，但bulletinWork/outOfServices/outOfService/document中的destinationName为空。

select X.Id, X.DestinationName from S1589_XML_Bulletin, XMLTABLE(
    '$d/*:bulletinWork'
    PASSING XMLTYPE(XML_RAW) as "d"
    COLUMNS
        Id                  VARCHAR2(50) PATH   '@*:id',
        DestinationName     VARCHAR2(50) PATH   '*:outOfServices/*:outOfService/*:document/*:destinationName'
) AS X

有人看到我在这里做错了吗？我需要得到：

Id                                       DestinationName
-------------------------------------    ------------------
5307cedc-2208-3701-9b9d-e69664b1ef31     MonsA
5307cedc-2208-3701-9b9d-e69664b1ef31     MonsB

Answer 1

 COLUMNS
        Id                  VARCHAR2(50) PATH   '@id',
        DestinationName     VARCHAR2(50) PATH   'string-join(distinct-values(*:outOfServices/*:outOfService/*:document/@destinationName),", ")'

您不必为未加前缀的属性使用命名空间。它们的名称空间定义为父元素。

在示例xml中有多个cern:outOfService这就是我使用string-join和distinct-values

的原因

更新：

1）它更长，但对我来说更清晰。两个xml表的连接。

    select * from xmltable('*:bulletinWork' passing xmltype('<cern:bulletinWork id="5307cedc-2208-3701-9b9d-e69664b1ef31" xmlns:cern="aaa">
      <cern:outOfServices>
        <cern:outOfService id="e95d491b-2876-3e08-901f-b0f79be86bfb">
          <cern:document destinationName="MonsA" type="S427"></cern:document>
        </cern:outOfService>
        <cern:outOfService id="fab04992-a33f-3a8c-ad16-29cd54fb93d6">
          <cern:document destinationName="MonsB" type="S427"></cern:document>
        </cern:outOfService>
      </cern:outOfServices>
    </cern:bulletinWork>')
    COLUMNS
            Id                  VARCHAR2(50) PATH   '@id',
            outOfServices       xmltype   path '*:outOfServices'  
    ) t1 
    ,xmltable('*:outOfServices/*:outOfService' passing t1.outOfServices 
    COLUMNS DestinationName     VARCHAR2(50) PATH   '*:document/@destinationName')

2）从子节点访问父节点。

select * from xmltable('*:bulletinWork/*:outOfServices/*:outOfService' passing xmltype('<cern:bulletinWork id="5307cedc-2208-3701-9b9d-e69664b1ef31" xmlns:cern="aaa">
  <cern:outOfServices>
    <cern:outOfService id="e95d491b-2876-3e08-901f-b0f79be86bfb">
      <cern:document destinationName="MonsA" type="S427"></cern:document>
    </cern:outOfService>
    <cern:outOfService id="fab04992-a33f-3a8c-ad16-29cd54fb93d6">
      <cern:document destinationName="MonsB" type="S427"></cern:document>
    </cern:outOfService>
  </cern:outOfServices>
</cern:bulletinWork>')
COLUMNS
        Id                  VARCHAR2(50) PATH   './../../@id', 
        DestinationName     VARCHAR2(50) PATH   '*:document/@destinationName'
)

XMLTable不从XML中的子级获取数据

1 个答案: