如何使用Akka HTTP表示表单数据请求?

时间:2018-04-26 15:00:20

标签: scala akka akka-http

我想使用Akka HTTP创建一个表单数据http请求到Facebook API。在curl中,请求示例如下所示:

curl \
 -X POST \
 "https://graph-video.facebook.com/v2.3/1533641336884006/videos"  \
 -F "access_token=XXXXXXX" \
 -F "upload_phase=transfer" \
 -F "start_offset=0" \
 -F "upload_session_id=1564747013773438" \
 -F "video_file_chunk=@chunk1.mp4"

因此,我为请求有效负载表示创建了以下模型:

case class FBSingleChunkUpload(accessToken: String, 
    sessionId: String,
    from: Long, 
    to: Long, 
    file: File) //file is always ~1Mb

然后我将使用:

Http().cachedHostConnectionPoolHttps[String]("graph-video.facebook.com")

但我不知道如何将FBSingleChunkUpload转换为正确的HttpRequest :(

您能否给我一个提示,如何使用Akka HTTP表示此类请求?

2 个答案:

答案 0 :(得分:2)

FormData Entity类型
 val fBSingleChunkUpload = ???
 HttpRequest(method = HttpMethods.POST,
              entity = FormData(("accessToken", fBSingleChunkUpload.accessToken), ...).toEntity)

此外,对于该文件,您可以检查它是否适用于Multipart.FormData

 val fileFormPart = Multipart.FormData
    .BodyPart("name", HttpEntity(MediaTypes.`application/octet-stream`, file.length(), FileIO.fromPath(file.toPath)))

  val otherPart = Multipart.FormData.BodyPart.Strict("accessToken", "the token")

  val entity =
    Multipart.FormData(otherPart, fileFormPart).toEntity

答案 1 :(得分:1)

在curl中,-F选项使用“multipart / form-data”内容类型规定POST。要在Akka HTTP中创建此类请求,请使用Multipart.FormData(下面的defaultEntity借用来自Akka HTTP的MultipartSpec):

val chunkUpload = FBSingleChunkUpload(...)

def defaultEntity(content: String) =
  HttpEntity.Default(ContentTypes.`text/plain(UTF-8)`, content.length, Source(ByteString(content) :: Nil))

val streamed = Multipart.FormData(Source(
  Multipart.FormData.BodyPart("access_token", defaultEntity(chunkUpload.accessToken)) ::
  Multipart.FormData.BodyPart("upload_phase", defaultEntity("transfer")) ::
  Multipart.FormData.BodyPart("start_offset", defaultEntity(chunkUpload.from.toString)) ::
  Multipart.FormData.BodyPart("upload_session_id", defaultEntity(chunkUpload.sessionId)) ::
  Multipart.FormData.BodyPart.fromFile(
    "video_file_chunk", ContentType.Binary(MediaTypes.`video/mp4`), chunkUpload.file
  ) :: Nil))

val request =
  HttpRequest(method = HttpMethods.POST, uri = /** your URI */, entity = streamed.toEntity)