Question

我需要具有近期状态的独特Jobid

jobs table
------------------ 
JobId Status CreatedDate 
------------------
1     sent   4/24/2018  
1     draft  4/23/2018 
2     sent   4/22/2018
2     draft  4/21/2018
1     req    4/20/2018

我需要这样的结果

---------------
JobId  Status
---------------
1       Sent
2       Sent

我尝试了这个但是给出了具有不同状态记录的重复jobid

select distinct JobId, Status, CreatedDate from Jobs order by CreatedDate desc

Answer 1

我建议：

select j.*
from jobs j
where j.CreatedDate = (select max(j2.CreatedDate) from jobs j2 where j2.jobid = j.jobid);

如果你有jobs(jobid, CreatedDate)的索引，那么这可能是最快的选择。

Answer 2

试试这个：

SELECT 
    JobId,
    Status
FROM
    jobs j,
    (
        SELECT JobId, max(CreatedDate) cd
        FROM jobs
        GROUP BY JobId
    ) as t
where j.jobid = t.jobid
and cd = j.CreatedDate

Answer 3

考虑到您使用的是支持Common-Table-Expressions的SQL Server版本，我将使用以下查询：

;with cte as (
    select 
        *, 
        ROW_NUMBER() over (PARTITION BY JobId ORDER BY CreatedDate desc) AS RN 
    from jobs)

select * from cte where RN = 1

在SQL查询中需要帮助以获取最近创建的具有状态的作业记录

3 个答案: