我实现了一个OSGi-bundle,它根据其service.xml获取了一些注入的其他服务。事实证明,如果激活策略设置为lazy,我的bundle会被激活。其他服务正确注入。
主要问题是,捆绑包启动和停止多次,具体取决于注入的其他服务的数量。如果我将注入的服务数量减少到只有一个,则只启动一次。通过注入5个其他服务,它启动和停止3次,其中最后一次启动没有停止,因此启动TCP服务器的服务正常工作。即使它工作正常,这种行为很奇怪,完全无意。
我不知道如何避免这种情况,因为我不知道这是怎么发生的。
LOG:
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting a 23347814 for instance 28219381
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting b 260627 for instance 28219381
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting c 22735430 for instance 28219381
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting d 4256633 for instance 28219381
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting e service 27446331 for instance 28219381
[Component Resolve Thread] INFO A.B.SimServiceComponent - Starting SimService now . . . 28219381
[Component Resolve Thread] INFO A.OTHER - starting component
[Component Resolve Thread] INFO A.OTHER - starting component
[Component Resolve Thread] INFO A.OTHER - starting component
[Component Resolve Thread] INFO A.OTHER - starting component
[Component Resolve Thread] INFO A.OTHER - starting component
[Component Resolve Thread] INFO A.B.SimServiceComponent - Stopping SimService now . . . 28219381
[Component Resolve Thread] INFO A.B.SimServiceComponent - SimService stopped.
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting a 23347814 for instance 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting b 260627 for instance 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting c 28883317 for instance 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting d 4256633 for instance 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting e service 27446331 for instance 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - Starting SimService now . . . 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - Stopping SimService now . . . 606383
[Component Resolve Thread] INFO A.B.SimServiceComponent - SimService stopped.
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting a 23347814 for instance 33352835
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting b 260627 for instance 33352835
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting c 31287346 for instance 33352835
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting d 4256633 for instance 33352835
[Component Resolve Thread] INFO A.B.SimServiceComponent - Setting e service 27446331 for instance 33352835
[Component Resolve Thread] INFO A.B.SimServiceComponent - Starting SimService now . . . 33352835
service.xml中:
<?xml version="1.0" encoding="UTF-8"?>
<scr:component xmlns:scr="http://www.osgi.org/xmlns/scr/v1.1.0" activate="activate" deactivate="deactivate" immediate="true" name="SimService">
<implementation class="SimServiceComponent"></implementation>
<service>
<provide interface="ServiceComponent"></provide>
</service>
<reference bind="setA" cardinality="1..1" interface="A" name="A" policy="static"/>
<reference bind="setB" cardinality="1..1" interface="B" name="B" policy="static"/>
<reference bind="setC" cardinality="1..1" interface="C" name="C" policy="static"/>
<reference bind="setD" cardinality="1..1" interface="D" name="D" policy="static"/>
<reference bind="setE" cardinality="1..1" interface="E" name="E" policy="static"/>
</scr:component>
激活服务设定者的方法和样本:
public void setA(final A a) {
LOG.info("Setting a {} for instance {} ", a.hashCode(), hashCode());
_a = a;
}
public void setB(final B b) {
LOG.info("Setting b {} for instance {} ", b.hashCode(), hashCode());
_b = b;
}
public void activate(BundleContext bundleContext) throws Exception {
LOG.info("Starting SimService now . . . {}", hashCode());
}
感谢您的帮助: - )
编辑:
此捆绑包内的服务不会被任何其他捆绑/服务使用,因此没有循环依赖关系。
答案 0 :(得分:3)
将哈希码标识添加到您的日志消息是明智之举!它表明虽然服务SQL> CREATE TABLE MANUFACTURER(M_NAME varchar2(75));
SQL> CREATE TABLE LINEITEM(l_manufacturer_name varchar2(75),l_partkey int);
SQL> INSERT INTO MANUFACTURER VALUES('abc');
SQL> INSERT INTO MANUFACTURER VALUES('def');
SQL> INSERT INTO LINEITEM VALUES('abc',1);
SQL> INSERT INTO LINEITEM VALUES('def',2);
SQL> INSERT INTO LINEITEM VALUES('abc',1);
SQL> INSERT INTO LINEITEM VALUES('def',2);
SQL> UPDATE LINEITEM a
SET a.l_manufacturer_name =
(SELECT CASE
WHEN MOD(b.L_PARTKEY, 2) = 0 THEN
(SELECT M_NAME FROM MANUFACTURER m WHERE ROWNUM = 1)
WHEN MOD(b.L_PARTKEY, 2) = 1 THEN
(SELECT M_NAME
FROM (SELECT M_NAME, ROWNUM AS MYROW
FROM (SELECT M_NAME, ROWNUM FROM MANUFACTURER m))
WHERE MYROW = 2)
END AS MANUFACTURER_NAME
FROM LINEITEM b
WHERE a.l_partkey = b.l_partkey);
ORA-01427: single-row subquery returns more than one row
SQL> UPDATE LINEITEM a
SET a.l_manufacturer_name =
(SELECT CASE
WHEN MOD(max(b.L_PARTKEY), 2) = 0 THEN
(SELECT M_NAME FROM MANUFACTURER m WHERE ROWNUM = 1)
WHEN MOD(max(b.L_PARTKEY), 2) = 1 THEN
(SELECT M_NAME
FROM (SELECT M_NAME, ROWNUM AS MYROW
FROM (SELECT M_NAME, ROWNUM FROM MANUFACTURER m))
WHERE MYROW = 2)
END AS MANUFACTURER_NAME
FROM LINEITEM b
WHERE a.l_partkey = b.l_partkey
GROUP BY b.L_PARTKEY );
4 row updated.
,A
,B
和D
是不变的,但服务E
的身份每次都会发生变化。
这意味着原始C
服务由于某种原因已从服务注册表中注销。由于您的C
组件对服务SimServiceComponent
具有强制1..1
引用,因此在C
消失时会强制停用。然后服务C
返回(更准确地说,已注册新的C
服务),允许重新激活您的组件。
因此,您需要了解C
服务循环的原因。