所以我的最终结果应该是这样的:
-----------------------------------------
| Release 1 and Release 2 Comparison |
-----------------------------------------
| VulnUnique1 |
| VulnUnique2 |
----------------------------------------
表1:工作区表
------------------------------
| Workspace | Name |
|-----------|----------------|
| 101 | Release1 |
| 102 | Release2 |
| 103 | Release3 |
| 104 | Release4 |
------------------------------
表2:漏洞表
------------------------------
| Workspace | Name |
|-----------|----------------|
| 101 | Vuln1 |
| 101 | Vuln2 |
| 101 | Vuln3 |
| 102 | Vuln1 |
| 102 | Vuln2 |
| 102 | Vuln3 |
| 102 | VulnUnique1 |
| 102 | VulnUnique2 |
------------------------------
答案 0 :(得分:0)
SELECT * FROM
vulnerability v
GROUP BY v.Name
HAVING Count(*)=1
<强>演示强>