将列表列表转换为pandas数据帧

时间:2018-04-22 07:29:04

标签: python python-3.x pandas dataframe

如何转换此列表(或数组?)

[((1538, 6323), (0.9995334, 0.9995334)), ((7694, 7862, 8399, 9158), array([0.99999015, 0.99997352, 0.99997993, 0.99996219]))]

到这个pandas数据帧

ClstId  ColInt  ColFloat
1       1538    0.9995334
1       6323    0.9995334
2       7694    0.99999015
2       7862    0.99997352
2       8399    0.99997993
2       9158    0.99996219

3 个答案:

答案 0 :(得分:1)

使用列表理解和展平:

||

答案 1 :(得分:0)

使用简单的迭代。

<强>演示:

import pandas as pd
import numpy as np
l = [((1538, 6323), (0.9995334, 0.9995334)), ((7694, 7862, 8399, 9158), np.array([0.99999015, 0.99997352, 0.99997993, 0.99996219]))]
d = {"ColInt": [], "ColFloat" : [], "ClstId": []}
for i, v in enumerate(l, 1):                    #use enumerate to get ClstId
    d["ColInt"].extend(list(v[0]))
    d["ColFloat"].extend(list(v[1]))
    d["ClstId"].extend([i]*len(v[0]))

df = pd.DataFrame(d)
print(df)

<强>输出:

   ClstId  ColFloat  ColInt
0       1  0.999533    1538
1       1  0.999533    6323
2       2  0.999990    7694
3       2  0.999974    7862
4       2  0.999980    8399
5       2  0.999962    9158

答案 2 :(得分:0)

试试这个,

In [18]: a = sum([zip(i[0],i[1]) for i in lst],[])

In [20]: df.DataFrame(a, columns=['ColInt','ColFloat'])
Out[20]: 
   ColInt  ColFloat
0    1538  0.999533
1    6323  0.999533
2    7694  0.999990
3    7862  0.999974
4    8399  0.999980
5    9158  0.999962