Question

大家好，我是蛋糕php的新手，并且正在努力使用Cake PHP代码的JSON响应格式

    public function getdata() {
    $responce = array();
    $conn = ConnectionManager::get('default');
    $stmt = $conn->execute('select * from mst_categories a inner join mst_subcategories b on a.category_id=b.category_id');
    $turnos = $stmt->fetchAll('assoc');
    $responce['status'] = 1;
    $responce['message'] = 'Category Data';
    $responce['data'] = $turnos;
    $this->set(compact('responce'));
    $this->set('_serialize', ['responce']);
}

结果我得到了JSON响应

{
"responce": {
    "status": 1,
    "message": "Category Data",
    "data": [
        {
            "category_id": "2",
            "category_name": "testing",
            "category_avtar": "C:\\xampp\\htdocs\\update\\webroot\\img\\cat_images\\5311-3.jpg",
            "subcategory_id": "1",
            "subcategory_name": "New Subcategory",
            "subcategory_avtar": "C:\\xampp\\htdocs\\update\\webroot\\img\\subcat_images\\8580-2820-3.jpg"
        },
        {
            "category_id": "2",
            "category_name": "testing",
            "category_avtar": "C:\\xampp\\htdocs\\update\\webroot\\img\\cat_images\\5311-3.jpg",
            "subcategory_id": "2",
            "subcategory_name": "Testing",
            "subcategory_avtar": "C:\\xampp\\htdocs\\update\\webroot\\img\\subcat_images\\1232-5311-3.jpg"
        }
    ]
  }
  }

虽然我想要按照描述的JSON输出

[
 {
  "categoryId": 11,
   "categoryName": "cloths",
   "subCategoryData": [
    {
   "subCategoryName": "jeans",
   "subCategoryId": 0
    },
   {
     "subCategoryName": "shirt",
     "subCategoryId": 1
   }
 ]
},
{
  "categoryId": 12,
  "categoryName": "electronics",
   "subCategoryData": [
    {
    "subCategoryName": "TV",
   "subCategoryId": 2
   },
  {
   "subCategoryName": "fridge",
   "subCategoryId": 3
   }
 ]
 }
]

我无法知道如何实现此类型的响应请在此查询中帮助我在打电话的时候

     $this->loadModel('MstCategories');
     $data= $this->MstSubcategories->find()->contain(['MstCategories']);
     $this->set(compact('data'));
     $this->set('_serialize', ['data']);

我得到这样的回复

  {
    "data": [
        {
        "subcategory_id": 1,
        "subcategory_name": "New Subcategory",
        "subcategory_avtar": "C:\\xampp\\htdocs\\update\\webroot\\\\img\\subcat_images\\8580-2820-3.jpg",
        "category_id": 2,
        "mst_category": {
            "category_id": 2,
            "category_name": "testing",
            "category_avtar": 
 "C:\\xampp\\htdocs\\niattaupdate\\webroot\\\\img\\cat_images\\5311-3.jpg"
          }
      },
      {
          "subcategory_id": 2,
          "subcategory_name": "Testing",
          "subcategory_avtar": "C:\\xampp\\htdocs\\niattaupdate\\webroot\\\\img\\subcat_images\\1232-5311-3.jpg",
         "category_id": 2,
        "mst_category": {
            "category_id": 2,
            "category_name": "testing",
            "category_avtar": "C:\\xampp\\htdocs\\niattaupdate\\webroot\\\\img\\cat_images\\5311-3.jpg"
         }
     }
 ]
 }

由于

Answer 1

您不需要执行SQL命令。如果您已经烘焙模型，可以尝试下面的代码

public function getdata()
{
    // if in controller other than MstCategoriesController
    $this->loadModel('MstCategories');

    $data = $this->MstCategories->find()
        ->contain([
            'MstSubcategories'
        ]);

    $this->set(compact('data'));
    $this->set('_serialize', ['data']);
}

使用CakePHP的两个表在Json中获取格式化的响应

1 个答案: