我有一个observable,我使用GroupBy
来获取许多流。我实际上想要在每个子流上得到Scan
结果。假设可观察量超过产品价格,扫描结果是每种产品类型的平均价格。
我有另外一系列与这些“产品”相关的事件(比如说“显示产品价格”事件),我想将它与之前的流的最新产品价格相结合。因此,每个组的Scan
输出需要与事件流的每个元素组合,以获得该事件产品的最新平均价格。
出于某种原因,我无法获得正确的语法,而且我整天都在抨击这一天。有人可以帮忙吗?
我在下面添加代码来说明近似意图。
public class Node
{
private List<int> Details = new List<int>();
public void AddInfo(int x)
{
Details.Add(x );
}
public Node(int x)
{
Details.Add(x);
}
public int Index => Details[0]%10; //just to simplify the grouping and debugging
public int Latest => Details.Last();
}
public class Message
{
private static Random _random = new Random();
public int MessageNodeInfo { get; private set; }
public Message()
{
MessageNodeInfo = _random.Next();
}
}
public class AccumulatingInfoTest
{
private static Random _random=new Random();
private IObservable<Message> MessageStream()
{
TimeSpan timeSpan = TimeSpan.FromSeconds(0.5);
var ret= Observable.Generate(0,
_ => { return true; },
_ => { return 0; },
_ => { return new Message(); },
_=> timeSpan)
.Publish()
.RefCount();
return ret;
}
public class ArbitraryCommonClass
{
public int K { get; set; }
public Message M { get; set; }
public Node D { get; set; }
public ArbitraryCommonClass Combine(ArbitraryCommonClass a)
{
return new ArbitraryCommonClass()
{
K = this.K,
M = this.M ?? a.M,
D = this.D ?? a.D
};
}
}
public void Start()
{
var inputStream = MessageStream();
inputStream.Subscribe(y => Console.WriteLine("Input: K " + y.MessageNodeInfo % 10 + " V " + y.MessageNodeInfo));
var nodeInfoStream = inputStream
.Select(nodeInfo => new Node(nodeInfo.MessageNodeInfo))
.GroupBy(node => node.Index)
.Select(groupedObservable => new
{
Key = groupedObservable.Key,
Observable = groupedObservable
.Scan(
(nodeAcc, node) => { nodeAcc.AddInfo(node.Latest); return nodeAcc; }
)
.Select(a => new ArbitraryCommonClass() { K = a.Index, M = (Message)null, D = a })
}
);
var groupedMessageStream =
inputStream
.GroupBy(
m => new Node(m.MessageNodeInfo).Index
)
.Select(a => new
{
Key =a.Key,
Observable = a.Select(b => new ArbitraryCommonClass() { K = a.Key, M = b, D = null })
});
var combinedStreams = nodeInfoStream
.Merge(groupedMessageStream)
.GroupBy(s => s.Key)
.Select(grp => grp
.Scan(
(state, next) => new { Key = state.Key, Observable = Observable.CombineLatest(state.Observable, next.Observable, (x, y) => { return x.Combine(y); }) }
)
)
.Merge()
.SelectMany(x => x.Observable.Select(a=>a));
combinedStreams.Where(x=>x.M!=null).Subscribe(x => Console.WriteLine(x.K + " " + x.M.MessageNodeInfo + " " + x.D.Latest));
}
}
答案 0 :(得分:1)
假设以下课程:
public class Product
{
public string Type { get; set; } = "Default";
public decimal Price { get; set; }
}
此处使用GroupBy
和Scan
(显示按类型分组的平均产品价格)。诀窍是Select
超过分组的observable到达各个分组,做任何事情,然后(大概)将它们合并在一起。您可以将Select
和Merge
折叠为单个SelectMany
,但在分开时可以更容易阅读:
var productSubject = new Subject<Product>();
var printSignal = new Subject<Unit>();
var latestAverages = productSubject.GroupBy(p => p.Type)
.Select(g => g
.Scan((0, 0.0m), (state, item) => (state.Item1 + 1, state.Item2 + item.Price)) //hold in state the count and the running total for each group
.Select(t => (g.Key, t.Item2 / t.Item1)) //divide to get the average
)
.Merge()
.Scan(ImmutableDictionary<string, decimal>.Empty, (state, t) => state.SetItem(t.Key, t.Item2)); //Finally, cache the average by group.
printSignal.WithLatestFrom(latestAverages, (_, d) => d)
.Subscribe(avgs =>
{
foreach (var avg in avgs)
{
Console.WriteLine($"ProductType: {avg.Key}. Average: {avg.Value}");
}
Console.WriteLine();
});
var productsList = new List<Product>()
{
new Product { Price = 1.00m },
new Product { Price = 2.00m },
new Product { Price = 3.00m },
new Product { Price = 2.00m, Type = "Alternate" },
new Product { Price = 4.00m, Type = "Alternate" },
new Product { Price = 6.00m, Type = "Alternate" },
};
productsList.ForEach(p => productSubject.OnNext(p));
printSignal.OnNext(Unit.Default);
productSubject.OnNext(new Product { Price = 4.0m });
printSignal.OnNext(Unit.Default);
productSubject.OnNext(new Product { Price = 8.0m, Type = "Alternate" });
printSignal.OnNext(Unit.Default);
这使用nuget包System.Collections.Immutable
。