PyQt5 - 对话框未通过按钮

时间:2018-04-17 03:49:39

标签: python pyqt5

我无法通过取消按钮关闭简单登录应用的对话框。

我绕圈试图解决这个问题,但我一直都不知道"属性错误"。

我使用pyuic5为ui生成ptyhon代码,然后将该部分复制到main.py的末尾

这段代码看起来与我在网上看到的其他例子不同

有什么建议吗?

Login_Dialog.py

from PyQt5 import QtCore, QtGui, QtWidgets

class Ui_loginDialog(object):
    def setupUi(self, loginDialog):
    loginDialog.setObjectName("loginDialog")
    loginDialog.resize(400, 300)
    self.newuser_pushButton = QtWidgets.QPushButton(loginDialog)
    self.newuser_pushButton.setGeometry(QtCore.QRect(50, 230, 75, 31))
    self.newuser_pushButton.setObjectName("newuser_pushButton")
    self.login_pushButton = QtWidgets.QPushButton(loginDialog)
    self.login_pushButton.setGeometry(QtCore.QRect(160, 230, 75, 31))
    self.login_pushButton.setObjectName("login_pushButton")
    self.cancel_pushButton = QtWidgets.QPushButton(loginDialog)
    self.cancel_pushButton.setGeometry(QtCore.QRect(270, 230, 75, 31))
    self.cancel_pushButton.setObjectName("cancel_pushButton")
    self.username_LineEdit = QtWidgets.QLineEdit(loginDialog)
    self.username_LineEdit.setGeometry(QtCore.QRect(140, 60, 201, 31))
    self.username_LineEdit.setObjectName("username_LineEdit")
    self.password_LineEdit = QtWidgets.QLineEdit(loginDialog)
    self.password_LineEdit.setGeometry(QtCore.QRect(140, 110, 201, 31))
    self.password_LineEdit.setEchoMode(QtWidgets.QLineEdit.Password)
    self.password_LineEdit.setObjectName("password_LineEdit")
    self.label = QtWidgets.QLabel(loginDialog)
    self.label.setGeometry(QtCore.QRect(30, 70, 91, 16))
    self.label.setObjectName("label")
    self.label_2 = QtWidgets.QLabel(loginDialog)
    self.label_2.setGeometry(QtCore.QRect(60, 120, 47, 13))
    self.label_2.setObjectName("label_2")

    self.retranslateUi(loginDialog)
    QtCore.QMetaObject.connectSlotsByName(loginDialog)

def retranslateUi(self, loginDialog):
    _translate = QtCore.QCoreApplication.translate
    loginDialog.setWindowTitle(_translate("loginDialog", "Login"))
    self.newuser_pushButton.setText(_translate("loginDialog", "New User"))
    self.login_pushButton.setText(_translate("loginDialog", "Login"))
    self.cancel_pushButton.setText(_translate("loginDialog", "Cancel"))
    self.label.setText(_translate("loginDialog", "Username (Email)"))
    self.label_2.setText(_translate("loginDialog", "Password"))

main.py

import sys
import Login_Dialog
from PyQt5 import QtCore, QtGui, QtWidgets
from Login_Dialog import Ui_loginDialog



class ui(Login_Dialog):

    def __init__(self):
        super(ui, self).__init__()
        self.cancel_pushButton.clicked.connect(self.reject)

    def reject(self):
        self.close()


if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    loginDialog = QtWidgets.QDialog()
    ui = Ui_loginDialog()
    ui.setupUi(loginDialog)
    loginDialog.show()
    sys.exit(app.exec_())

1 个答案:

答案 0 :(得分:0)

您的代码有以下错误:

  • Login_Dialog是指.py文件,它不是一个类,所以你不能继承它。

  • Qt Designer仅提供用于填充窗口小部件的设计类,它不是窗口小部件。 PyQt建议创建一个新的小部件并使用Qt Designer提供的类来填充它。

  • 拒绝是一种QDialog方法,因此您可以直接连接它,关闭窗口而不使用close()

综上所述,您的代码应如下所示:

import sys
from PyQt5 import QtCore, QtGui, QtWidgets
from Login_Dialog import Ui_loginDialog

class ui(QtWidgets.QDialog, Ui_loginDialog):
    def __init__(self):
        super(ui, self).__init__()
        self.setupUi(self)
        self.cancel_pushButton.clicked.connect(self.reject)


if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    w = ui()
    w.show()
    sys.exit(app.exec_())