创建名为'securityConfiguration'的bean时出错：通过字段'userDetailsS​​ervice'表示不满意的依赖关系

Question

我正在尝试创建一个Spring Boot应用程序，它使用Spring Security和OAuth2通过数据库进行身份验证。我正在尝试关注此存储库的GitHub示例（https://github.com/TechPrimers/spring-security-db-example），现在面临此错误。

段落式StackTrace：

org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'securityConfiguration': Unsatisfied dependency expressed through field 'userDetailsService'; nested exception is org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'userDetailsDervice': Unsatisfied dependency expressed through field 'usersRepository'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'usersRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.Optional com.user.path.to.repository.UsersRepository.findByName(java.lang.String)! No property name found for type AccountUser!

Caused by: org.springframework.beans.factory.UnsatisfiedDependencyException: Error creating bean with name 'userDetailsDervice': Unsatisfied dependency expressed through field 'usersRepository'; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'usersRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.Optional com.user.path.to.repository.UsersRepository.findByName(java.lang.String)! No property name found for type AccountUser!

Caused by: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'usersRepository': Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.Optional com.user.path.to.repository.UsersRepository.findByName(java.lang.String)! No property name found for type AccountUser!

Caused by: java.lang.IllegalArgumentException: Failed to create query for method public abstract java.util.Optional com.user.path.to.repository.UsersRepository.findByName(java.lang.String)! No property name found for type AccountUser!

Caused by: org.springframework.data.mapping.PropertyReferenceException: No property name found for type AccountUser!

以下是我的课程：

CustomUserDetailsS​​ervice

  @Service("userDetailsDervice")
  public class CustomUserDetailsService implements UserDetailsService {

  @Autowired
  private UsersRepository usersRepository;


  @Override
  public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
    Optional<AccountUser> optionalUsers = usersRepository.findByName(username);

    optionalUsers
            .orElseThrow(() -> new UsernameNotFoundException("Username not found"));
    return optionalUsers
            .map(CustomUserDetails::new).get();
  }
}

UsersRepository

@Repository
public interface UsersRepository extends JpaRepository<AccountUser, Integer> {
    Optional<AccountUser> findByName(String username);
}

AccountUser

@Entity
@Table(name = "User")
public class AccountUser {

@Column(name = "title")
private String title;

@Column(name = "firstname")
private String firstname;

@Column(name = "lastname")
private String lastName;

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
@Column(name = "email")
private String email;

@Column(name = "password")
private String password;

@Column(name = "modified")
private Date modified;

@Column(name = "accessed")
private Date accessed;

/* ... getters and setters ....*/

Answer 1

@Repository
public interface UsersRepository extends JpaRepository<AccountUser, Integer> {
    Optional<AccountUser> findByName(String username);
}

替换为以下

@Repository
public interface UsersRepository extends JpaRepository<AccountUser, Integer> {
    Optional<AccountUser> findByLastName(String username);
}

您没有将Name作为实体的一部分，JPA无法找到属性 “名称”

订购时需要

  

@Repository公共接口UsersRepository扩展   JpaRepository {可选   findByLastNameOrderByAccessedDesc（String username）; }

在这里，您将找到jpa查询的示例 https://docs.spring.io/spring-data/jpa/docs/1.5.0.RELEASE/reference/html/jpa.repositories.html  特别是在本节表2.3。方法名称中支持的关键字