Question

我需要有关SQL过程的帮助。我已经尝试并尽我所能，但以下程序不起作用，需要帮助，为什么它不起作用，

.navbarfooter {
  display: inline-block;
}
.navbarfooter {
 display: flex;
 justify-content: center;
 margin: 0 auto;
}
.navbarfooter-mainlink:nth-child(n+2):before {
 content: ""; 
 display: inline-block; 
 height: 10px; 
 width: 1px; 
 background-color: hsla(0,0%,4%,.3); 
 margin: 0 15px; 
 pointer-events: none;  
}
.navbarfooter-mainlink {
 white-space: nowrap;
}
.navbarfooter-mainlink {
 font-size: 17px;
 display: inline-block;
 white-space: nowrap;
 padding: 5px;
}

@media only screen and (max-width: 740px) {
 .navbarfooter {
  flex-wrap: wrap;
 }
}

以上更新为学生查询并插入查询两者单独工作。但不是在插入CREATE PROCEDURE updateUser (IN ID INT(11), name VARCHAR(100), email VARCHAR(100), role VARCHAR(9), gender VARCHAR(6), birthday VARCHAR(10), classroom INT(11) ) SET TRANSACTION ISOLATION LEVEL SERIALIZABLE; BEGIN TRANSACTION; IF EXISTS (SELECT * FROM student WHERE userID = ID) BEGIN UPDATE tbl_users SET userName = name, userEmail = email, userRole = role, gender = gender, birthday = birthday WHERE userID = ID; UPDATE student SET classID = classroom WHERE userID = ID; END ELSE BEGIN UPDATE tbl_users SET userName = name, userEmail = email, userRole = role, gender = gender, birthday = birthday WHERE userID = ID; INSERT INTO student(classID, userID) VALUES (classroom, ID); END COMMIT TRANSACTION;时。

Answer 1

因为您使用的是MySQL。请尝试以下代码，看看它是否有效，

CREATE PROCEDURE updateUser
     (IN ID INT(11), 
      name VARCHAR(100), 
      email VARCHAR(100), 
      role VARCHAR(9), 
      gender VARCHAR(6), 
      birthday VARCHAR(10), 
      classroom INT(11) )  


   BEGIN
       IF EXISTS (SELECT * FROM student WHERE userID = ID) THEN
       START TRANSACTION;
           UPDATE tbl_users 
           SET userName = name, userEmail = email, userRole = role, 
               gender = gender, birthday = birthday 
           WHERE userID = ID;

           UPDATE student 
           SET classID = classroom 
           WHERE userID = ID;
       COMMIT;
       ELSE
       START TRANSACTION;
           UPDATE tbl_users 
           SET userName = name, userEmail = email, userRole = role, 
               gender = gender, birthday = birthday 
           WHERE userID = ID;

           INSERT INTO student(classID, userID) 
           VALUES (classroom, ID);

       COMMIT;
       END IF;
   END;

如果存在则更新其他插入不起作用

1 个答案: