我试图用虚拟节点(centinels)实现Dequeue。当我试图编译时,我得到一个分段错误11错误。这是我的代码:(非常感谢!!)
Node.h:
#ifndef LINKEDDEQUE_H
#define LINKEDDEQUE_H
#include "Node.h"
#include <iostream>
using namespace std;
template <class Element>
class LinkedDeque {
public:
LinkedDeque();
~LinkedDeque();
LinkedDeque(const LinkedDeque<Element>& deque);
bool isEmpty()const;
void insertFront(const Element & element);
void insertRear(const Element & element);
void deleteFront();
void deleteRear();
void print();
const Element& getFront()const;
const Element& getRear()const;
private:
int num_elements;
Node<Element> *_front;
Node<Element> *_rear;
Node<Element> *frontSentinel;
Node<Element> *rearSentinel;
};
template <class Element>
LinkedDeque<Element>::LinkedDeque(){
//creamos nodos vacios
_front->setNext(frontSentinel);
_rear->setPrevious(rearSentinel); //**************
int num_elements = 0;
cout << "Holi" << endl;
}
//cal implementar el constructor copia
template <class Element>
LinkedDeque<Element>::LinkedDeque(const LinkedDeque<Element>& deque){
}
template <class Element>
LinkedDeque<Element>::~LinkedDeque() {
}
template <class Element>
bool LinkedDeque<Element>::isEmpty()const{
return (this->frontSentinel->getNext()==nullptr);
}
template <class Element>
void LinkedDeque<Element>::insertFront(const Element & element){
Node<Element> *new_node = new Node<Element> (element);
if(isEmpty()){
rearSentinel->setPrevious(new_node);
frontSentinel->setNext(new_node);
}else{
Node<Element> *aux;
aux = frontSentinel->getNext();
frontSentinel->setNext(new_node);
aux->setPrevious(frontSentinel->getNext());
delete aux;
}
num_elements++;
}
template <class Element>
void LinkedDeque<Element>::insertRear(const Element & element){
Node<Element> *new_node = new Node<Element> (element);
if(isEmpty()){
rearSentinel->setPrevious(new_node);
frontSentinel->setNext(new_node);
}else{
Node<Element> *aux;
aux = rearSentinel->getPrevious();
rearSentinel->setPrevious(new_node);
aux->setNext(rearSentinel->getPrevious());
delete aux;
}
num_elements++;
}
template <class Element>
void LinkedDeque<Element>::deleteFront(){
if(!isEmpty()){
if(num_elements == 1){
delete frontSentinel->getNext();
frontSentinel->setNext(rearSentinel);
rearSentinel->setPrevious(frontSentinel);
}else {
Node<Element> *aux;
aux = frontSentinel->getNext();
aux->getNext()->setPrevious(frontSentinel);
frontSentinel->setNext(aux->getNext());
delete aux;
}
num_elements--;
}
}
template <class Element>
void LinkedDeque<Element>::deleteRear(){
if(!isEmpty()){
if(num_elements == 1){
delete rearSentinel->getPrevious();
rearSentinel->setPrevious(nullptr);
frontSentinel->getPrevious(nullptr);
}else{
Node<Element> *aux;
aux = rearSentinel->getPrevious();
aux->getPrevious()->setNext(rearSentinel);
rearSentinel->setPrevious(aux->getPrevious());
delete aux;
}
num_elements--;
}
}
template <class Element>
void LinkedDeque<Element>::print(){
if(!isEmpty()){
Node<Element> *printController = frontSentinel->getNext();
while( printController->getNext()!= nullptr){
cout<< printController->getElement() << endl;
printController = printController->getNext();
}
}
}
template <class Element>
const Element& LinkedDeque<Element>::getFront()const{
return frontSentinel->getNext()->getElement();
}
template <class Element>
const Element& LinkedDeque<Element>::getRear()const{
return rearSentinel->getPrevious()->getElement();
}
#endif /* LINKEDDEQUE_H */
LinkedDeque.h:
#include <cstdlib>
#include"Node.h"
#include"LinkedDeque.h"
using namespace std;
/*
*
*/
int main(int argc, char** argv) {
LinkedDeque<int> *deque= new LinkedDeque<int>;
deque->insertFront(4);
deque->insertFront(5);
deque->insertRear(10);
deque->deleteFront();
deque->print();
}
最后,main.cpp:
{{1}}
也许我不应该实现Node的析构函数并为它虚拟化?或者指针声明有一些错误?
答案 0 :(得分:0)
我猜你的LinkedDeque构造函数模板正在访问无效的_front,_rear指针
template <class Element>
LinkedDeque<Element>::LinkedDeque(){
//creamos nodos vacios
_front->setNext(frontSentinel); //*_front has not been initialized and contains undefined values*
_rear->setPrevious(rearSentinel); //**************
int num_elements = 0;
cout << "Holi" << endl;
}
答案 1 :(得分:0)
您可以使用new Node<Element>(NULL);
构建标记,以便LinkedDeque
有Node<Element>
个对象用作标记而不是nullptr
。从以下方法中的这些更改开始:
template <class Element>
LinkedDeque<Element>::LinkedDeque(){
//creamos nodos vacios
frontSentinel = new Node<Element>(NULL);
rearSentinel = new Node<Element>(NULL);
rearSentinel->setPrevious(frontSentinel);
frontSentinel->setNext(rearSentinel);
int num_elements = 0;
cout << "Holi" << endl;
}
template <class Element>
bool LinkedDeque<Element>::isEmpty()const{
return this->frontSentinel->getNext()->getElement()==NULL;
}
template <class Element>
void LinkedDeque<Element>::insertFront(const Element & element){
Node<Element> *new_node = new Node<Element>(element);
new_node->setNext(frontSentinel->getNext());
frontSentinel->getNext()->setPrevious(new_node);
new_node->setPrevious(frontSentinel);
frontSentinel->setNext(new_node);
num_elements++;
}
template <class Element>
void LinkedDeque<Element>::insertRear(const Element & element){
Node<Element> *new_node = new Node<Element> (element);
new_node->setPrevious(rearSentinel->getPrevious());
rearSentinel->getPrevious()->setNext(new_node);
new_node->setNext(rearSentinel);
rearSentinel->setPrevious(new_node);
num_elements++;
}
template <class Element>
void LinkedDeque<Element>::deleteFront(){
Node<Element> *aux = frontSentinel->getNext();
aux->getNext()->setPrevious(frontSentinel);
frontSentinel->setNext(aux->getNext());
delete aux;
num_elements--;
}
template <class Element>
void LinkedDeque<Element>::deleteRear(){
Node<Element> *aux = rearSentinel->getPrevious();
aux->getPrevious()->setNext(rearSentinel);
rearSentinel->setPrevious(aux->getPrevious());
delete aux;
num_elements--;
}
template <class Element>
void LinkedDeque<Element>::print(){
Node<Element> *printController = frontSentinel->getNext();
while (printController->getElement() != NULL) {
cout << printController->getElement() << endl;
printController = printController->getNext();
}
}