我有一个按钮下拉列表
<div class="form-group">
<button type="button" class="btn btn-secondary dropdown-toggle form-group" (click)="get()" data-toggle="dropdown"
aria-haspopup="true" aria-expanded="false">
<span id="selected">View Domains</span>
</button>
<div class="dropdown-menu arrow form-group">
<button class="dropdown-item" type="button" value="1">1</button>
<button class="dropdown-item" type="button" value="2">2</button>
<button class="dropdown-item" type="button" value="3">3</button>
</div>
</div>
$('.dropdown-menu button').click(function(){
$('#selected').text($(this).text());
});
我希望在选择任何选项(1,2,3)时获取组件中的下拉值,例如:如果他们选择1,我应该能够在组件中获得值= 1,并保存它到localStorage。
答案 0 :(得分:1)
在click
上使用<div class="dropdown-menu arrow form-group">
事件,更新HTML,如下所示。
<div class="dropdown-menu arrow form-group" (click)="onSelect($event)">
然后在组件中添加onSelect
方法,如下所示。
onSelect(event) {
localStorage.setItem("selectedItem", event.target.value);
// Do the rest
}
答案 1 :(得分:1)
myText = 'View Domains'
select(val){
this.myText = val;
localStorage.setItem('myText', this.myText);
}
模板中的
<div class="form-group">
<button type="button" class="btn btn-secondary dropdown-toggle form-group" (click)="get()" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
<span id="selected">{{myText}}</span>
</button>
<div class="dropdown-menu arrow form-group">
<button class="dropdown-item" type="button" value="1" (click)="select(1)">1</button>
<button class="dropdown-item" type="button" value="2" (click)="select(2)">2</button>
<button class="dropdown-item" type="button" value="3" (click)="select(3)">3</button>
</div>
</div>