Question

我正在尝试更改单个密钥标签及其miniKeybord（popupKeyboard）资源ID其更改标签但是当我按下该密钥时其不更改miniKeyboard资源ID 我在候选视图中切换按钮，我想从中更改“。” “ - ”键入其更改的标签但不是longPress的ResourceID

这是我更改键标签和ResourceID的切换方法

 public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {


    this.editor = this.mSharedPreferences.edit();
    switch (buttonView.getId()) {
        case R.id.easyUrduToggleBtn:
            if (isChecked) {
                this.editor.putBoolean("easy_urdu", true);
                this.mEasyUrdu = shouldChangePunctuationKey = true;
                SoftKeyboard keyboard = (SoftKeyboard) mKeyboardSwitcher.getInputView().getKeyboard();
                keyboard.mPunctuationKey.label = "۔";
                keyboard.mPunctuationKey.codes = new int[]{keyboard.mPunctuationKey.label.charAt(0)};
                keyboard.mPunctuationKey.popupResId = R.xml.popup_punctuation_ur;
                mKeyboardSwitcher.getInputView().invalidateKey(keyboard.mPunctuationKey);

            } else {
                this.editor.putBoolean("easy_urdu", false);
                this.mEasyUrdu = shouldChangePunctuationKey = false;
                SoftKeyboard keyboard = (SoftKeyboard) mKeyboardSwitcher.getInputView().getKeyboard();
                keyboard.mPunctuationKey.label = ".";
                keyboard.mPunctuationKey.codes = new int[]{keyboard.mPunctuationKey.label.charAt(0)};
                keyboard.mPunctuationKey.popupResId = R.xml.popup_punctuation;
                mKeyboardSwitcher.getInputView().invalidateKey(keyboard.mPunctuationKey);
            }
            this.editor.apply();
            return;
        default:
            return;
    }
}

这是KeyboardBaseView

中的invalidateKey方法

 public void invalidateKey(Key key) {
    if (key == null)
        return;
    mInvalidatedKey = key;
    // TODO we should clean up this and record key's region to use in onBufferDraw.
    mDirtyRect.union(key.x + getPaddingLeft(), key.y + getPaddingTop(),
            key.x + key.width + getPaddingLeft(), key.y + key.height + getPaddingTop());
    onBufferDraw();
    invalidate(key.x + getPaddingLeft(), key.y + getPaddingTop(),
            key.x + key.width + getPaddingLeft(), key.y + key.height + getPaddingTop());
}

它只是通过重绘它而不是miniKeyboardResource id来改变它的标签，当我长按其显示的旧miniKeyboard但是当我点击下一个EditText时它改变了资源ID，因为我在这个方法中检入了class SoftKeyboard extends Keyboard

 @Override
protected Key createKeyFromXml(Resources res, Row parent, int x, int y,
                               XmlResourceParser parser) {
    Key key = new LatinKey(res, parent, x, y, parser);
    switch (key.getCode()) {
        case 46:
            mPunctuationKey=key;
            if (LatinIME.shouldChangePunctuationKey) {
                key.label = "۔";
                key.codes = new int[]{key.label.charAt(0)};
                key.popupResId=R.xml.popup_punctuation_ur;
                mPunctuationKey=key;
                Log.e("akjskjas",1+"");

            } else {
                key.label = ".";
                key.codes = new int[]{key.label.charAt(0)};
                key.popupResId=R.xml.popup_punctuation;
                Log.e("akjskjas",2+"");

            }
            break;

但是从切换按钮不能正常工作它只更改标签而不是miniKeyboard key.popupResId请帮我解决问题

SoftKeyboard invalidateKey（Key key）无法按预期工作

0 个答案: