我正在尝试使用SpringBoot 2.0和新的反应式webFlux库。我想知道如何将通过无阻塞WebClient进行的两次调用的结果返回给我的Springboot API的调用者。我的代码是:
@RequestMapping("/search")
public CombinedResults perfomSearch(@RequestParam final String searchTerm) {
Mono<SearchResponse> fasMono = searchService.getSearchResults(searchTerm, "fh");
Mono<SearchResponse> esMono = searchService.getSearchResults(searchTerm, "es");
CombinedResults combinedResults = new CombinedResults(fasMono, esMono);
return combinedResults;
}
CombinedResult对象只是一个POJO:
public class CombinedResults {
private Mono<SearchResponse> fasSearchResponse;
private Mono<SearchResponse> esSearchResponse;
public CombinedResults(final Mono<SearchResponse> fasSearchResponse, final Mono<SearchResponse> esSearchResponse) {
this.fasSearchResponse = fasSearchResponse;
this.esSearchResponse = esSearchResponse;
}
public Mono<SearchResponse> getFasSearchResponse() {
return fasSearchResponse;
}
public void setFasSearchResponse(final Mono<SearchResponse> fasSearchResponse) {
this.fasSearchResponse = fasSearchResponse;
}
public Mono<SearchResponse> getEsSearchResponse() {
return esSearchResponse;
}
public void setEsSearchResponse(final Mono<SearchResponse> esSearchResponse) {
this.esSearchResponse = esSearchResponse;
}
但是如果我称之为我回复的回复是
{
"fasSearchResponse": {
"scanAvailable": true
},
"esSearchResponse": {
"scanAvailable": true
}
}
而不是SearchResponse对象的内容。我觉得我可能会错过这个应该如何运作的基本要点!我的想法是,因为WebClient没有阻塞,我可以解雇两个Web服务调用,然后将它们组合起来而不需要可完成的期货等?
答案 0 :(得分:4)
Spring WebFlux不支持嵌套的响应类型。 你应该这样做:
Mono<SearchResponse> fasMono = searchService.getSearchResults(searchTerm, "fh");
Mono<SearchResponse> esMono = searchService.getSearchResults(searchTerm, "es");
Mono<CombinedResults> results = fasMono.zipWith(esMono,
(fas, es) -> {return new CombinedResults(fas, es);});
答案 1 :(得分:3)
我认为您应该返回一个对象的Mono,该对象代表通过此操作响应的模型。假设CombinedResults
是您的模型。这个类应该是这样的:
public class CombinedResults {
private SearchResponse fasSearchResponse;
private SearchResponse esSearchResponse;
public CombinedResults(final SearchResponse fasSearchResponse, final SearchResponse esSearchResponse) {
this.fasSearchResponse = fasSearchResponse;
this.esSearchResponse = esSearchResponse;
}
//... getters AND/OR setters
}
并且,在您的控制器上,您可以执行以下操作:
@RequestMapping("/search")
public Mono<CombinedResults> perfomSearch(@RequestParam final String searchTerm) {
Mono<SearchResponse> fasMono = searchService.getSearchResults(searchTerm, "fh");
Mono<SearchResponse> esMono = searchService.getSearchResults(searchTerm, "es");
Mono<CombinedResults> combinedResults =
fasMono
.flatMap(fh -> esMono.map(es -> new CombinedResults(fh, es)));
return combinedResults;
}
通过这种方式,您将返回一个Mono对象,其中包含您想要的响应。当两个Mono都发出项目时,带有fasMono.flatMap
的操作链esMono.map
会构建CombinedResults
。当尝试将两个Monos连接成一个时,这种组合很常见。我想你也可以使用zip
运算符加入Monos。
所有这些都与WebClient无关。如果您的getSearchResults
仅执行异步非阻塞操作,则所有内容都是异步非阻塞。