您好我正在尝试在我的网站中使用地理数据,而我无法动态提取餐馆的地址并将其放入我的javascript中。我正在使用get方法从网址中提取restaurant_id,然后使用它来提取餐厅的完整地址。这是我遇到问题的代码行(var destinationAddress):
$con=mysqli_connect("root","");
$rest_id2=$_GET['id'];
$rest_id=(int)$rest_id2;
$sql="SELECT * from restaurant WHERE restaurant_id='".$rest_id."'";
$result=mysqli_query($con,$sql);
$rows=mysqli_fetch_assoc($result);
?>
<!DOCTYPE html>
<html>
<head>
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script type="text/javascript" src="https://maps.googleapis.com/maps/api/js?sensor=true"></script>
<script>
$(document).ready(function() {
//exit early if no geolocation
if(!navigator.geolocation) return;
var destinationAddress = "<?php echo $rows['address'].$rows['city'].$rows['state'].$rows['zip']; ?>";
</script>
</head>
....
任何人都知道我在这里做错了吗?
答案 0 :(得分:0)
尝试添加逗号和空格。
var destinationAddress = "<?php echo $rows['address'].$rows['city'].$rows['state'].$rows['zip']; ?>";
答案 1 :(得分:0)
因为忘记关闭函数})
,请尝试
<script>
$(document).ready(function() {
//exit early if no geolocation
if(!navigator.geolocation) return;
var destinationAddress = "<?php echo $rows['address'].$rows['city'].$rows['state'].$rows['zip']; ?>";
})
</script>
答案 2 :(得分:0)
让您的生活更轻松:在模板之外构建目标地址:
private string GetTextFromPage(PdfReader pdfReader, int page)
{
StringBuilder pageText = new StringBuilder();
var cpage = pdfReader.GetPageN(page);
var content = cpage.Get(PdfName.CONTENTS);
//Error for casting Pdfarray to PRIndirectReference
var indirectReference = (PRIndirectReference)content;
}
然后简单地
$rows=mysqli_fetch_assoc($result);
if( $rows !== NULL )
{
$destinationAddress = "{$rows['address']}, {$rows['city']}, {$rows['state']}, {$rows['zip']}";
}
else
{
// no rows! (anomaly)
$destinationAddress = "no destination address available";
}
// due to the way you'll later inject the variable
// into JavaScript code double quotes must be escaped
$destinationAddress = str_replace( '"', '\"', $destinationAddress );