我已经按照此链接在我的laravel博客应用中创建数据库通知,当一个用户喜欢其他用户的帖子时
https://laravel.com/docs/5.5/notifications#database-notifications
我的应用程序成功创建了数据库通知,如下所示
表格:通知
id |类型| notifiable_id | notifiable_type |数据| read_at | created_at |的updated_at
id = 0b2a7fdf-eea4-4982-a86d-e874bb4f28ef
type = App\Notifications\PostLiked
notifiable_id= 48
data = { "event":"LIKE",
"postid":17,
"sender":{
"id":50,
"name":"Developer",
}
}
read_at = NULL
created_at = 2018-04-07 12:46:42
updated_at = 2018-04-07 12:46:42
现在我想通过data-> postid
删除数据库通知行我在下面尝试过查询:
DB::table('notifications')
->where('type','App\Notifications\PostLiked')
->where('data->postid',17)
->first();
得到错误:
QueryException SQLSTATE [42000]:语法错误或访问冲突:1064 您的SQL语法有错误;检查手册 对应于您的MariaDB服务器版本,以获得正确的语法 靠近'' $。" postid"' = 17)限制1'在第1行(SQL:select * from 通知where(type = App \ Notifications \ PostLiked 和数据 - >' $。" postid"' = 17)限制1)
我也试过以下查询:
$结果= DB ::表('通知') - > whereRaw(" JSON_EXTRACT(数据, ' $ .postid')=?",[17]);
{
connection: { },
grammar: { },
processor: { },
bindings: {
select: [ ],
join: [ ],
where: [
17
],
having: [ ],
order: [ ],
union: [ ]
},
aggregate: null,
columns: null,
distinct: false,
from: "notifications",
joins: null,
wheres: [
{
type: "raw",
sql: "JSON_EXTRACT(`data`, '$.postid') = ?",
boolean: "and"
}
],
groups: null,
havings: null,
orders: null,
limit: null,
offset: null,
unions: null,
unionLimit: null,
unionOffset: null,
unionOrders: null,
lock: null,
operators: [
"=",
"<",
">",
"<=",
">=",
"<>",
"!=",
"<=>",
"like",
"like binary",
"not like",
"between",
"ilike",
"&",
"|",
"^",
"<<",
">>",
"rlike",
"regexp",
"not regexp",
"~",
"~*",
"!~",
"!~*",
"similar to",
"not similar to",
"not ilike",
"~~*",
"!~~*"
],
useWritePdo: false
}
请建议我正确查询以通过通知表
中的json(data.key)获取行和删除行答案 0 :(得分:1)
MariaDB不支持这种用于查询JSON列的表示法。
您可以使用原始SQL:
->whereRaw("JSON_EXTRACT(`data`, '$.postid') = ?", [17])
答案 1 :(得分:0)
DB::table('notifications')
->where('type','App\Notifications\PostLiked')
->where('data->postid',17)
->first();
我猜这里的错误是 where(&#39; data-&gt; postid&#39;,17)。查看其中(&#39; name_column_in_table&#39;,&#39;值&#39;); 表 data-&gt;帖子
中不能包含字段名称答案 2 :(得分:0)
对我有用。您可以使用以下查询:
textPdf