Question

我必须从文件中读取XML，即：

<?xml version="1.0" encoding="UTF-16"?>
   <KyactusProfileClass xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <username>sadasdsad</username> 
      <userid>0067AA87BF9AD466792E1A20F6AAB7F</userid>
      <useDefaultFolder>false</useDefaultFolder>
      <autoAcceptDownloads>false</autoAcceptDownloads>
      <visible>false</visible>
   </KyactusProfileClass>

我使用以下代码阅读：

using (var xmlReader = XmlReader.Create(pathXML))
{
    Console.WriteLine(File.ReadAllText(pathXML));
    schemas.Add(null, xmlReader);
}

但我得到以下错误：

System.Xml.Schema.XmlSchemaException：'W3C XML Schema的根元素必须是＆lt;架构＆gt;它的名字必须是'http://www.w3.org/2001/XMLSchema'。'

我使用XML序列化程序和XSD Schema验证器生成了该XML：

<xs:schema attributeFormDefault="unqualified" elementFormDefault="qualified"
           xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <xs:element name="kyactusprofile" type="kyactusprofile" />
  <xs:complexType name="kyactusprofile" >
    <xs:sequence>
    <xs:element type="xs:string" name="username" maxOccurs="1" minOccurs="1"/>
    <xs:element type="xs:string" name="userid"  maxOccurs="1" minOccurs="1"/>
    <xs:element type="xs:boolean" name="useDefaultFolder"  maxOccurs="1" minOccurs="1"/>
    <xs:element type="xs:string" name="defaultFolder"  maxOccurs="1" minOccurs="1"/>
    <xs:element type="xs:boolean" name="autoAcceptDownloads"  maxOccurs="1" minOccurs="1"/>
    <xs:element type="xs:boolean" name="visible"  />
    </xs:sequence>
  </xs:complexType>
</xs:schema>

她是堆栈跟踪：

System.Xml.Schema.XmlSchemaException
  HResult=0x80131941
  Message=L'elemento radice di W3C XML Schema deve essere <schema> e il suo spazio dei nomi deve essere 'http://www.w3.org/2001/XMLSchema'.
  Source=System.Xml
  StackTrace:
   at System.Xml.Schema.XmlSchemaSet.InternalValidationCallback(Object sender, ValidationEventArgs e)
   at System.Xml.Schema.XmlSchemaSet.SendValidationEvent(XmlSchemaException e, XmlSeverityType severity)
   at System.Xml.Schema.XmlSchemaSet.ParseSchema(String targetNamespace, XmlReader reader)
   at System.Xml.Schema.XmlSchemaSet.Add(String targetNamespace, XmlReader schemaDocument)
   at Kyactus.XmlManager.GestoreXml.ValidateXmlWithXsd(String pathXML) in C:\Users\Cristiano\Documents\Visual Studio 2017\Projects\progetto-pds\visual-studio\Kyactus\Kyactus\XmlManager\GestoreXml.cs:line 249
   at Kyactus.XmlManager.GestoreXml.UnmarshallProfile() in C:\Users\Cristiano\Documents\Visual Studio 2017\Projects\progetto-pds\visual-studio\Kyactus\Kyactus\XmlManager\GestoreXml.cs:line 178
   at Kyactus.XmlManager.GestoreXml..ctor() in C:\Users\Cristiano\Documents\Visual Studio 2017\Projects\progetto-pds\visual-studio\Kyactus\Kyactus\XmlManager\GestoreXml.cs:line 64
   at Kyactus.App..ctor() in C:\Users\Cristiano\Documents\Visual Studio 2017\Projects\progetto-pds\visual-studio\Kyactus\Kyactus\App.xaml.cs:line 21
   at Kyactus.App.Main()

Answer 1

您最有可能阅读XML

<?xml version="1.0" encoding="UTF-16"?>
   <KyactusProfileClass xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
      <username>sadasdsad</username> 
      <userid>0067AA87BF9AD466792E1A20F6AAB7F</userid>
      <useDefaultFolder>false</useDefaultFolder>
      <autoAcceptDownloads>false</autoAcceptDownloads>
      <visible>false</visible>
   </KyactusProfileClass>

使用XmlReader并尝试将其添加为XmlSchema。这是错误的方法，它不是架构！您必须阅读XSD，然后才会显示Exception。

XmlSchemaException C＃

1 个答案: