我创建了一种“处理”对话框,它显示了某个进程的进程。它包含一个进度条和一个Label。这是代码:
public class ProcessingDialog
{
FrontWindow win;
public ProcessingDialog(int min, int max, string initialMessage,string title, bool isContineous)
{
Thread th= new Thread(new ThreadStart(delegate()
{
win = new FrontWindow();
win.Title = title;
if (isContineous == false)
{
win.ProgressBarProgress.Minimum = min;
win.ProgressBarProgress.Maximum = max;
}
else
win.ProgressBarProgress.IsIndeterminate = true;
win.LabelStatus.Content = initialMessage;
win.ShowInTaskbar = false;
win.Topmost = true;
win.ShowDialog();
}
));
th.SetApartmentState(ApartmentState.STA);
th.Start();
}
public void Increment(int margin)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value+=margin; }), null); ;
}
public void Reset()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value=0; }), null); ;
}
public void ChangeMessage(string message)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.LabelStatus.Content=message; }), null); ;
}
public void Close()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.Close(); }), null); ;
}
}
这是FrontWindow的标记:
<Window x:Class="WpfApplicationUnleashed.FrontWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="FrontWindow" Height="165" Width="300" WindowStyle="ThreeDBorderWindow" WindowStartupLocation="CenterOwner" ResizeMode="NoResize">
<DockPanel>
<ProgressBar x:FieldModifier="public" x:Name="ProgressBarProgress" Height="15" Margin="20" DockPanel.Dock="Top" VerticalAlignment="Top"></ProgressBar>
<Label x:FieldModifier="public" x:Name="LabelStatus" Margin="10" VerticalAlignment="Top" HorizontalAlignment="Left" DockPanel.Dock="Bottom"></Label>
</DockPanel>
</Window>
这是我显示对话框的窗口。它只包含一个按钮,其点击事件是这样的:
private void button1_Click(object sender, RoutedEventArgs e)
{
ProcessingDialog pd = new ProcessingDialog(0, 10, "Starting", "Processing", false);
Thread.Sleep(1000);
pd.ChangeMessage("Step 1");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 2");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 3");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 4");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 5");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 6");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 7");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 8");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 9");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 10");
pd.Increment(1);
Thread.Sleep(1000);
pd.Close();
}
问题在于,当它显示时,如果我再次单击该按钮,当对话框关闭时,它会再次打开。我的意思是它没有被点击,因为它是模态,但它只是排队,当对话框关闭时,它被点击。
如何防止这种情况发生?
答案 0 :(得分:0)
可能bind a command到该按钮并编写一个CanExecute方法,该方法会阻止命令执行(如果该命令已在进行中)。
答案 1 :(得分:0)
如果在前窗打开时不打算使用后窗,我会在前窗上设置一个事件来禁用后窗,然后在关闭时启用后窗。