您好,我试图以GB为单位获取所有数据库的总大小
我从这个命令开始,每个人的工作都很好,但我无法获得所有数据库的总数!!
任何想法如何获得最终所有数据库的总大小。
这是我的命令
mysql> SELECT table_schema AS "Database name", SUM(ROUND(((DATA_LENGTH + INDEX_LENGTH) / 1024 / 1024 /1024 ), 2)) AS "Size (GB)" FROM information_schema.TABLES GROUP BY table_schema;
答案 0 :(得分:0)
您可以使用jetty9_version=9.2.22.v20170606
jetty94_version=9.4.6.v20170531
选项。
[HttpGet]
public JsonResult FetchCoIds(string CoName)
{
var data = new { Value = "val", Text = CoName+"_val1" };
return Json(data, JsonRequestBehavior.AllowGet);
}
在此处阅读:https://dev.mysql.com/doc/refman/5.7/en/group-by-modifiers.html
答案 1 :(得分:0)
我正在使用此查询:
$db->executeSQL("SELECT table_schema, SUM((data_length+index_length)) AS BytesUsed FROM information_schema.tables WHERE table_schema='$DBName'");
$db_size = $db->arrayedResult[0]['BytesUsed'];
echo "calculating DB: $DBName - size: " . $db_size . "\n";
并显示:
/**
* format size to Kb, Mb, Gb format
*
* @param $size
* @return string
*/
public static function formatSize($size)
{
$units = explode(' ', 'B KB MB GB TB PB');
$mod = 1024;
for ($i = 0; $size >= $mod; $i++)
{
$size /= $mod;
}
$endIndex = strpos($size, ".") + 3;
$ret = substr($size, 0, $endIndex) . ' ' . $units[$i];
return $ret;
}