Question

我的代码有问题，我无法显示数据库中的数据我正在使用bindParam（）和bindValue（）它仍然无效。

这是我的代码：

$id = $_GET['id'];
try{
    $database = new Connection();
    $db = $database->openConnection();

    $sql = "SELECT users.username, users.user_id, topic.*, post.* 
            FROM users INNER JOIN post
            ON users.user_id = post.user_id
            INNER JOIN topic
            ON topic.topic_id = post.topic_id
            WHERE topic.topic_id = :id";

    $stm = $db->prepare($sql);
    $stm->bindValue(":id", $id);
    $stm->execute();
    $row = $stm->fetch();

    foreach($db->query($sql) as $row){
        echo "<td>". $row['content'] . "</td>";
    }

}catch(PDOException $e){
    echo 'Connection Problem: '. $e->getMessage();
}

我收到此错误：

 Connection Problem: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ':id' at line 6

但是当我使用时

$sql = "SELECT users.username, users.user_id, topic.*, post.* 
            FROM users INNER JOIN post
            ON users.user_id = post.user_id
            INNER JOIN topic
            ON topic.topic_id = post.topic_id
            WHERE topic.topic_id = ". $id;

$stm = $db->prepare($sql);
$stm->execute();

完美无缺

提前致谢

Answer 1

在bindValue()代码中，您的循环错误。你应该循环遍历数组$row它应该是

foreach($row as $value){
   echo "<td>". $value['content'] . "</td>";
}

SQL bindParam不工作

1 个答案: