Question

感谢您的关注！这是我的问题：我有一个有退出选项的菜单栏。单击时，将弹出一个窗口，提示用户输入管理员访问密码，然后再允许他们退出主应用程序我一遍又一遍地改变了我的代码但仍然遇到了同样的问题这是我现在的代码

def exitmenu():

def exitmenucheck():
    if passwordentry.get() == actualpassword:
        quit
    else:
        popupmsg("error")

exitmenu= tk.Tk()
exitmenu.wm_title("Administrator Access")

label = ttk.Label(exitmenu, text="Enter Password.", font=NORM_FONT)
label.grid(row=0,column=0)

password = tk.StringVar()
passwordentry = tk.Entry(exitmenu, textvariable=password, show='*')
passwordentry.grid(row=0,column=1)

button = ttk.Button(exitmenu, text="Exit", command=exitmenucheck, width=8)
button.bind('<Enter>',exitmenucheck)
button.grid(row=2,column=1,sticky="s")

这是我输入正确或错误密码时出现的错误

Exception in Tkinter callback
Traceback (most recent call last):
  File "/usr/lib/python3.5/tkinter/__init__.py", line 1562, in __call__
    return self.func(*args)
TypeError: exitmenucheck() takes 0 positional arguments but 1 was given
Exception in Tkinter callback
Traceback (most recent call last):
  File "/usr/lib/python3.5/tkinter/__init__.py", line 1562, in __call__
    return self.func(*args)
TypeError: exitmenucheck() takes 0 positional arguments but 1 was given

抱歉，我2天前才启动python编程，所以这看起来像是一个非常简单的任务，不可能搞砸。感谢您提前耐心和指导：）

Answer 1

这应该actualpassword为字符串'actualpassword'，因此通过向其添加parenthesis来更改该部分。

def exitmenucheck():
    if passwordentry.get() == 'actualpassword':
        quit
    else:
        popupmsg("error")

从您的代码中查看此示例

import tkinter as tk
from tkinter import ttk
from tkinter import messagebox   


def exitmenu():
    pass

def exitmenucheck(event=None):
    if passwordentry.get() == "actualpassword":
        exitmenu.destroy()
    else:
        messagebox.showwarning("error", "password incorrect")
       # popupmsg("error")
        print("error")


exitmenu= tk.Tk()
exitmenu.wm_title("Administrator Access")

label = ttk.Label(exitmenu, text="Enter Password.")
label.grid(row=0,column=0)

password = tk.StringVar()
passwordentry = tk.Entry(exitmenu, textvariable=password, show='*')
passwordentry.bind("<Return>", exitmenucheck)
passwordentry.grid(row=0,column=1)

button = ttk.Button(exitmenu, text="Exit", command=exitmenucheck, width=8)
# button.bind('<Enter>',exitmenucheck)
button.grid(row=2,column=1,sticky="s")

exitmenu.mainloop()

你应该bind你的entry小部件而不是button小部件，你应该绑定keyboard enter key而不是Return

尝试创建密码提示和检查器以允许退出程序

1 个答案: