我的数据类似于：
SId Program Term Year Grad term Grad year
-------------------------------------------------------------------
1 P 2 2001 3 2005
1 P 3 2001 3 2005
1 P 2 2002 3 2005
2 M 2 2002 2 2004
2 M 3 2002 2 2004
现在，我能够根据一个列'日期'组合记录，但在我的情况下，我需要检查年份和期限，以确保它们是连续的，然后将它们组合。（对于每年，术语从1-3）开始。因此，在执行查询后，结果应为：
SID Program startterm startyear EndTerm EndYear Gradterm Gradyear
--------------------------------------------------------------------------
1 P 2 2001 3 2001 3 2005
1 P 2 2002 2 2002 3 2005
2 M 2 2002 3 2002 2 2004
连续年份和期限的记录合并在一起，程序-P，第2期，2002年的记录与之前的记录不连续，因此记录将以相同的一行结束开始期限，开始年份和结束期限，结束年份。非常感谢任何帮助。
答案 0 :(得分：1)
检查此查询是否适用于您。使用您正在使用的列替换列和表。
Select o.Program ,min(o.Term) AS StartTerm,
o.year AS StartYear,
max(Term) AS EndTerm,
(Select max(g.year) from #GradProg g where g.[Grad term] =
o.[Grad term] AND g.Program = o.Program AND g.[Grad
year] = o.[Grad year]) AS EndYear,
[Grad term],[Grad year]
from #GradProg o
group by Program ,[Grad term],[Grad year],Year
order by [Grad year] desc
答案 1 :(得分：1)
此查询取决于术语列的值，如果值介于1和3之间，则可以使用。它用于查找连续范围
declare @t table (Id int, Program char(1), Term int, Year int, GradTerm int, GradYear int)
insert into @t
values (1, 'P', 2, 2001, 3, 2005)
, (2, 'P', 3, 2001, 3, 2005), (3, 'P', 2, 2002, 3, 2005)
, (4, 'M', 2, 2002, 2, 2004), (5, 'M', 3, 2002, 2, 2004)
select
ID = row_number() over (order by grp), Program, startterm = min(Term)
, startyear = min(Year), EndTerm = max(Term), EndYear = max(Year), GradTerm, GradYear
from (
select
*, grp = Year * 3 + Term - row_number() over (partition by Program, GradTerm, GradYear order by Year, Term)
from
@t
) t
group by Program, GradTerm, GradYear, grp
输出：
ID Program startterm startyear EndTerm EndYear GradTerm GradYear
-----------------------------------------------------------------------
1 P 2 2001 3 2001 3 2005
2 P 2 2002 2 2002 3 2005
3 M 2 2002 3 2002 2 2004
修改
SID应位于group by，您还需要将其放入row_number。另外，我在答案中的查询有一些错误。因此，你可能会得到错误的结果。这是一个正确的版本
declare @t table (SID int, Program char(1), Term int, Year int, GradTerm int, GradYear int)
insert into @t
values (1, 'P', 2, 2001, 3, 2005)
, (1, 'P', 3, 2001, 3, 2005), (1, 'P', 2, 2002, 3, 2005)
, (2, 'M', 2, 2002, 2, 2004), (2, 'M', 3, 2002, 2, 2004)
select
SID, Program, startterm = right(min(val), 1)
, startyear = left(min(val), 4), EndTerm = right(max(val), 1)
, EndYear = left(max(val), 4), GradTerm, GradYear
from (
select
*, grp = Year * 3 + Term - row_number() over (partition by SID, Program, GradTerm, GradYear order by Year, Term)
, val = concat(Year, Term)
from
@t
) t
group by SID, Program, GradTerm, GradYear, grp
答案 2 :(得分：0)
public void ConnectMachineIClock(string IP)
{
int idwErrorCode = 0;
var Iclock = IclockDetails.Where(a => a.IpAddress == IP).FirstOrDefault();
if (AttnMachineRepository.IsMachineOnline(IP) == true)
{
Stopwatch sw = Stopwatch.StartNew();
blnCon = CZKEM1.Connect_Net(IP.Trim(), 4370);
sw.Stop();
if (blnCon == true)
{
UpdateText(1, txtStatus, Iclock.IpAddress);
iMachineNumber = Iclock.Id;
LocId = Iclock.LocationId;
MType = Iclock.MachineTypeId;
LocName = AttnMachineRepository.GetPunchLocation(LocId);
CZKEM1.RegEvent(iMachineNumber, 65535);
UpdateText(2, txtStatus, Iclock.IpAddress);
//txtStatus.BeginInvoke((Action)(() => txtStatus.Text += ("Connected with " + Iclock.IpAddress + " " + sw.Elapsed.TotalSeconds + " Seconds taken to connect") + Environment.NewLine));
MachineIP = Iclock.IpAddress;
Get_IClock_LogData(iMachineNumber);
}
else
{
CZKEM1.GetLastError(ref idwErrorCode);
UpdateText(-1, txtErrorLog, Iclock.IpAddress);
//txtErrorLog.BeginInvoke((Action)(() => txtErrorLog.Text += "Unable to connect the device with IP: " + MachineIP + ", ErrorCode = " + idwErrorCode.ToString() + "" + Environment.NewLine));
//Application.DoEvents();
}
}
else
{
UpdateText(-2, txtErrorLog, Iclock.IpAddress);
//txtErrorLog.BeginInvoke((Action)(() => txtErrorLog.Text += "IP " + MachineIP + " not found" + Environment.NewLine));
//Application.DoEvents();
}
}
public void UpdateText(int status, TextBox text, string IP)
{
switch (status)
{
case 1:
text.BeginInvoke((Action)(() => text.Text += ("Data Processing for" + IP + " starts") + Environment.NewLine));
Application.DoEvents();
break;
case 2:
text.BeginInvoke((Action)(() => text.Text += ("Connected with " + IP) + Environment.NewLine));
Application.DoEvents();
break;
case -1:
text.BeginInvoke((Action)(() => text.Text += "Unable to connect the device with IP: " + IP + ", ErrorCode = " + -1 + "" + Environment.NewLine));
Application.DoEvents();
break;
case -2:
text.BeginInvoke((Action)(() => text.Text += "IP " + IP + " not found" + Environment.NewLine));
Application.DoEvents();
break;
}
}
答案 3 :(得分：0)
试试这个
create table #tmp (id int, Program VARCHAR(1),Term INT,[Year] INT,[Grad Term] INT, [Grad year] INT)
insert into #tmp
SELECT 1,'P',2,2001,3,2005
union
SELECT 2,'P',3,2001,3,2005
union
SELECT 3,'P',2,2002,3,2005
union
SELECT 4,'M',2,2002,2,2004
union
SELECT 5,'M',3,2002,2,2004
;with cte
AS(
select *,
RANK() OVER(partition by Program,[Year] order by id,[year],term) as [Minrank],
RANK() OVER(partition by Program,[Year] order by id desc,[year]desc,term desc) as [Maxrank]
from #tmp
)
select c1.id,c2.Program,c1.term as Startterm,c1.[year] as StartYear,
c2.term as EndTerm, c2.[Year] As EndYear,c1.[Grad Term],c2.[Grad year] from cte c1
JOIN cte c2 on c1.Program=c2.program and c1.[year]=c2.[year] and c1.Minrank=c2.[Maxrank]
WHERE c1.Minrank=1
order by c1.id
drop table #tmp