我正在尝试使用import UIKit
struct Products: Decodable {
let products: [product]
}
struct product: Decodable {
let title: String
let id: Int
let price: String
let sale_price: String?
let featured_src: String?
let short_description: String
}
class ViewController: UIViewController {
override func viewDidLoad() {
super.viewDidLoad()
let jsonUrlString = "https://www.komeil24.com/wc-api/v3/products"
guard let url = URL(string: jsonUrlString) else {return}
URLSession.shared.dataTask(with: url) { (data, response, error) in
guard let data = data else {return}
do {
let products = try JSONDecoder().decode(Products.self, from: data)
print(products.products)
} catch let jsonErr {
print("Error" , jsonErr)
}
}.resume()
}
}
来解析大量的xml文件，以便我可以将它们转换为数据帧，但是，当我尝试解析实际的xml文件时，我得到错误：
xml2dict这个错误对于所有xml文件都是完全相同的，包括“第1行，第5列”，它们的长度差异很大，但结构上都是相同的。
当我尝试在xthon中将xml文件的内容复制为字符串时，使用xml2dict进行解析非常有效。例如：
"ExpatError: not well-formed (invalid token): line 1, column 5"
在上面的示例中xmlstr ="""<?xml version="1.0" encoding="utf-8"?>
<document id="DDI-DrugBank.d200">
<sentence id="DDI-DrugBank.d200.s0" text="Co-administration of probenecid with acyclovir has been shown to increase the mean half-life and the area under the concentration-time curve.">
<entity id="DDI-DrugBank.d200.s0.e0" charOffset="21-30"
type="drug" text="probenecid"/>
<entity id="DDI-DrugBank.d200.s0.e1" charOffset="37-45"
type="drug" text="acyclovir"/>
<pair id="DDI-DrugBank.d200.s0.p0" e1="DDI-DrugBank.d200.s0.e0"
e2="DDI-DrugBank.d200.s0.e1" ddi="true" type="mechanism"/>
</sentence>
<sentence id="DDI-DrugBank.d200.s1" text="Urinary excretion and renal clearance were correspondingly reduced."/>
<sentence id="DDI-DrugBank.d200.s2" text="The clinical effects of this combination have not been studied."/>
</document>"""
import xmltodict as x2d
nestdict1 = x2d.parse('Train/DrugBank/Aciclovir_ddi.xml')
nestdict2 = x2d.parse(xmlstr)
引发了错误，而nestdict1仍然正常，尽管nestdict2是文件xmlstr的直接复制和粘贴
答案 0 :(得分：1)
您需要传递文件对象，而不是文件名的字符串。
来自docs：
In [4]:print(xmltodict.parse.__doc__)
Parse the given XML input and convert it into a dictionary.
`xml_input` can either be a `string` or a file-like object.
因此，创建一个文件描述符，如：
fd = open("Train/DrugBank/Aciclovir_ddi.xml")
然后将其传递给解析方法：
x2d.parse(fd)