我想请所有朋友帮我解决问题。
我有几个想要连接的表。
id | name_cust | idmd_pic -----------------------------+-------------------------- 10 | CF Sukajadi Bandung | 7 11 | SPM Toserba Griya Dinasti | 7 12 | SPM Toserba Yogya GATSU | 7 13 | SPM Toserba Yogya Lucky Square | 17 14 | PT Transretail Indonesia/ Sukajadi| 7
id | idcust | name_cust | visit_date | idmd_visit -----------------------------+--------------------------------------------------- 20 | 12 | SPM Toserba Yogya GATSU | 2018-03-23 | 7 21 | 13 | SPM Toserba Yogya Lucky Square | 2018-03-23 | 17 22 | 11 | SPM Toserba Griya Dinasti | 2018-03-23 | 7 23 | 14 | PT Transretail Indonesia/ Sukajadi | 2018-03-24 | 7 24 | 11 | SPM Toserba Griya Dinasti | 2018-03-24 | 7 25 | 10 | CF Sukajadi Bandung | 2018-03-24 | 7 26 | 13 | SPM Toserba Yogya Lucky Square | 2018-03-24 | 7 27 | 12 | SPM Toserba Yogya GATSU | 2018-03-24 | 7 28 | 11 | SPM Toserba Griya Dinasti | 2018-03-29 | 17
id | name_md | visit_rotation -----------------------------+-------------------------- 7 | Nunu Nugraha | 9 17 | Erwin | 10
我想生成这样的数据
id | name_cust | idmd_pic | visit_date | idmd_visit | visit_rotation | -----------------------------+------------------------------------------------------------ 10 | CF Sukajadi Bandung | 7 | 2018-03-24 | 7 | 9 11 | SPM Toserba Griya Dinasti | 7 | 2018-03-24 | 7 | 9 12 | SPM Toserba Yogya GATSU | 7 | 2018-03-24 | 7 | 9 13 | SPM Toserba Yogya Lucky Square | 17 | 2018-03-23 | 17 | 10 14 | PT Transretail Indonesia/ Sukajadi| 7 | 2018-03-24 | 7 | 9
这里我很困惑如何使数据可以像那样显示,我无法按照其idmd_pic和最新访问日期显示数据,希望这里的朋友可以帮忙,谢谢。
答案 0 :(得分:1)
SELECT c.id,
c.name_cust,
c.idmd_pic,
max(dt.visit_date) as visit_date,
dt.idmd_visit,
dm.visit_rotation
From customer c
inner join details_the dt
on c.id=dt.idcust
and c.idmd_pic=dt.idmd_visit
inner join datamd dm
on c.idmd_pic=dm.id
GROUP BY C.id
ORDER BY c.id
现场演示