我遵循Angular Material的材料表示例,目前,他们对表格示例进行了过滤,并在结果中输入了类型。
我在材质表示例中添加了两个下拉列表,我希望能够从两个下拉列表中选择一个值,并根据两个下拉列表中的两个值执行搜索。例如。在这种情况下,如果我选择8和氢,我不应该得到任何结果,因为8和氢不是同一记录/项目的一部分。如果我选择1和氢,我应该回氢,因为1和氢值是同一项目/记录的一部分。
这里是stackbiltz:https://stackblitz.com/edit/angular-t67ae3-huzvd6?file=app%2Ftable-filtering-example.ts
以下是代码段:
组件:
import {Component} from '@angular/core';
import {MatTableDataSource} from '@angular/material';
/**
* @title Table with filtering
*/
@Component({
selector: 'table-filtering-example',
styleUrls: ['table-filtering-example.css'],
templateUrl: 'table-filtering-example.html',
})
export class TableFilteringExample {
displayedColumns = ['position', 'name', 'weight', 'symbol'];
dataSource = new MatTableDataSource(ELEMENT_DATA);
//How do I filter based on selected value?
search(selectedValue: string, selectedValueEle: string) {
selectedValue = selectedValue.trim(); // Remove whitespace
selectedValue = selectedValue.toLowerCase(); // MatTableDataSource defaults to lowercase matches
this.dataSource.filter = selectedValue && selectedValueEle;
debugger
}
}
export interface Element {
name: string;
position: number;
weight: number;
symbol: string;
}
const ELEMENT_DATA: Element[] = [
{position: 1, name: 'Hydrogen', weight: 1.0079, symbol: 'H'},
{position: 2, name: 'Helium', weight: 4.0026, symbol: 'He'},
{position: 3, name: 'Lithium', weight: 6.941, symbol: 'Li'},
{position: 4, name: 'Beryllium', weight: 9.0122, symbol: 'Be'},
{position: 5, name: 'Boron', weight: 10.811, symbol: 'B'},
{position: 6, name: 'Carbon', weight: 12.0107, symbol: 'C'},
{position: 7, name: 'Nitrogen', weight: 14.0067, symbol: 'N'},
{position: 8, name: 'Oxygen', weight: 15.9994, symbol: 'O'},
{position: 9, name: 'Fluorine', weight: 18.9984, symbol: 'F'},
{position: 10, name: 'Neon', weight: 20.1797, symbol: 'Ne'},
{position: 11, name: 'Sodium', weight: 22.9897, symbol: 'Na'},
{position: 12, name: 'Magnesium', weight: 24.305, symbol: 'Mg'},
{position: 13, name: 'Aluminum', weight: 26.9815, symbol: 'Al'},
{position: 14, name: 'Silicon', weight: 28.0855, symbol: 'Si'},
{position: 15, name: 'Phosphorus', weight: 30.9738, symbol: 'P'},
{position: 16, name: 'Sulfur', weight: 32.065, symbol: 'S'},
{position: 17, name: 'Chlorine', weight: 35.453, symbol: 'Cl'},
{position: 18, name: 'Argon', weight: 39.948, symbol: 'Ar'},
{position: 19, name: 'Potassium', weight: 39.0983, symbol: 'K'},
{position: 20, name: 'Calcium', weight: 40.078, symbol: 'Ca'},
];
html:
<div class="example-container mat-elevation-z8">
<div class="example-header">
<select #selectedValueEle>
<option value="8">8</option>
<option value="9">9</option>
</select>
<select #selectedValue>
<option value="Hydrogen">Hydrogen</option>
<option value="Helium">Helium</option>
</select>
<button (click)="search(selectedValue.value, selectedValueEle.value)">Search</button>
<mat-form-field>
<input matInput (keyup)="applyFilter($event.target.value)" placeholder="Filter">
</mat-form-field>
</div>
<mat-table #table [dataSource]="dataSource">
<!-- Position Column -->
<ng-container matColumnDef="position">
<mat-header-cell *matHeaderCellDef> No. </mat-header-cell>
<mat-cell *matCellDef="let element"> {{element.position}} </mat-cell>
</ng-container>
<!-- Name Column -->
<ng-container matColumnDef="name">
<mat-header-cell *matHeaderCellDef> Name </mat-header-cell>
<mat-cell *matCellDef="let element"> {{element.name}} </mat-cell>
</ng-container>
<!-- Weight Column -->
<ng-container matColumnDef="weight">
<mat-header-cell *matHeaderCellDef> Weight </mat-header-cell>
<mat-cell *matCellDef="let element"> {{element.weight}} </mat-cell>
</ng-container>
<!-- Symbol Column -->
<ng-container matColumnDef="symbol">
<mat-header-cell *matHeaderCellDef> Symbol </mat-header-cell>
<mat-cell *matCellDef="let element"> {{element.symbol}} </mat-cell>
</ng-container>
<mat-header-row *matHeaderRowDef="displayedColumns"></mat-header-row>
<mat-row *matRowDef="let row; columns: displayedColumns;"></mat-row>
</mat-table>
</div>
答案 0 :(得分:1)
如果您更换该行:
this.dataSource.filter = selectedValue && selectedValueEle;
使用:
this.dataSource.filter = selectedValueEle + selectedValue;
应该做的伎俩!
这是因为根据Angular表文档https://material.angular.io/components/table/overview#filtering:
例如,数据对象{id:123,名称:'先生Smith',favoriteColor:'blue'}将减少到123mr。 smithblue。如果您的过滤字符串是蓝色的,那么它将被视为匹配,因为它包含在缩减字符串中,并且该行将显示在表格中。
根据我的理解,他们正在进行简单的字符串搜索。因此,通过连接值和元素,它在“1Hydrogen”上进行字符串搜索,并在简化数据对象“1Hydrogen1.0079H”中找到它。
但是你必须按照“1Hydrogen”的顺序排列它,所以让selectedValueEle
成为第一个和selectedValue
接下来,你将拥有正确的格式。希望这有帮助,祝你好运!