我遇到了一个Android测试应用程序的问题。 我有2个表单，在表单1中首先输入用户名，然后输入用户的姓，然后在表单2中输入他们的信息。 所有这些都可以使用单个表单完成，但我决定使用2个表单来完成，因为我想学习如何使用数据库中表之间的关系。
第一种形式有效，数据加载到数据库上，但是第二种形式存在问题，我不加载数据。
我尝试插入第一个表单的Query的id，并将其与第二个文件.php中的会话一起传递，以将其插入外部键中。
但它不起作用。
你能告诉我为什么，我错了吗？
我有两张桌子：'Persone'和'Persone2' 第一个'Persone'表有字段：id（PK），Name和Surname（VARCHAR）
第二个表'Persone2'包含以下字段：idP2（PK），FK_persone（外键），团队，角色和数字（VARCHAR）
第一种形式的.php文件
<?php
session_start();
if($_SERVER['REQUEST_METHOD']=='POST'){
include 'C.php';
$con = mysqli_connect($HostName,$HostUser,$HostPass,$DatabaseName);
$Nome = $_POST['Nome'];
$Cognome = $_POST['Cognome'];
$CheckSQL = "SELECT * FROM Persone WHERE Nome = '$Nome'";
$check = mysqli_fetch_array(mysqli_query($con,$CheckSQL));
if(isset($check)){
echo 'Utente già registrato';
}
else{
$Sql_Query = "INSERT INTO Persone (Nome, Cognome) values ('$Nome','$Cognome')";
$People_id = mysqli_insert_id($con);
$_SESSION ['People_id'] = $People_id;
if(mysqli_query($con,$Sql_Query))
{
echo 'Registration Successfully';
}
else
{
echo 'Something went wrong';
}
}
}
mysqli_close($con);
?>
第二种形式的.php文件
<?php
session_start();
if($_SERVER['REQUEST_METHOD']=='POST'){
include 'C.php';
$con = mysqli_connect($HostName,$HostUser,$HostPass,$DatabaseName);
$Squadra = $_POST['Squadra'];
$Ruolo = $_POST['Ruolo'];
$Numero_maglia = $_POST['Numero_maglia'];
$CheckSQL = "SELECT * FROM Persone, Persone2 WHERE Persone2.FK_persone = '" . ($_SESSION ['People_id']). "'";;
$check = mysqli_fetch_array(mysqli_query($con,$CheckSQL));
if(isset($check)){
echo 'Utente già registrato';
}
else{
$Sql_Query = "INSERT INTO Persone2 (FK_persone, Squadra, Ruolo, Numero_maglia) values ('" . ($_SESSION ['People_id']). "','$Squadra', '$Ruolo', '$Numero_maglia')";
if(mysqli_query($con,$Sql_Query))
{
echo 'Registration Successfully';
}
else
{
echo 'Something went wrong';
}
}
}
mysqli_close($con);
?>
与第二种形式相关的android研究的Java文件
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.Window;
import android.widget.Button;
import android.widget.EditText;
import android.app.ProgressDialog;
import android.os.AsyncTask;
import android.os.Build;
import android.support.annotation.RequiresApi;
import android.support.v7.app.AppCompatActivity;
import android.text.TextUtils;
import android.widget.Toast;
import java.net.FileNameMap;
import java.util.HashMap;
public class Activity2 extends AppCompatActivity {
private EditText id, squadra, ruolo, numeromaglia;
private Button registrazionee;
//REGISTRAZIONE
String Squadra_Holder, Ruolo_Holder, Numero_Maglia_Holder;
String finalResult ;
String HttpURLRegister = "http://provaord.altervista.org/NEW/R22.php";
Boolean CheckEditText ;
ProgressDialog progressDialog;
HashMap<String,String> hashMap = new HashMap<>();
HttpParse httpParse = new HttpParse();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_2);
// id = (EditText)findViewById(R.id.editText6);
squadra = (EditText)findViewById(R.id.editText7);
ruolo = (EditText)findViewById(R.id.editText3);
numeromaglia = (EditText)findViewById(R.id.editText4);
registrazionee = (Button)findViewById(R.id.button55);
registrazionee.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
// Checking whether EditText is Empty or Not
CheckEditTextIsEmptyOrNot();
if(CheckEditText){
// If EditText is not empty and CheckEditText = True then this block will execute.
UserRegisterFunction(Squadra_Holder, Ruolo_Holder, Numero_Maglia_Holder);
}
else {
// If EditText is empty then this block will execute .
Toast.makeText(Activity2.this, "Please fill all form fields.", Toast.LENGTH_LONG).show();
}
}
});
}
//REGISTRAZIONE
public void CheckEditTextIsEmptyOrNot(){
Squadra_Holder = squadra.getText().toString();
Ruolo_Holder = ruolo.getText().toString();
Numero_Maglia_Holder = numeromaglia.getText().toString();
if(TextUtils.isEmpty(Squadra_Holder) || TextUtils.isEmpty(Ruolo_Holder) || TextUtils.isEmpty(Numero_Maglia_Holder) )
{
CheckEditText = false;
}
else {
CheckEditText = true ;
}
}
//REGISTRATION
@RequiresApi(api = Build.VERSION_CODES.CUPCAKE)
public void UserRegisterFunction(final String Squadra, final String Ruolo, final String Numero_maglia){
class UserRegisterFunctionClass extends AsyncTask<String,Void,String> {
@Override
protected void onPreExecute() {
super.onPreExecute();
progressDialog = ProgressDialog.show(Activity2.this,"Loading Data",null,true,true);
}
@Override
protected void onPostExecute(String httpResponseMsg) {
super.onPostExecute(httpResponseMsg);
progressDialog.dismiss();
Toast.makeText(Activity2.this,httpResponseMsg.toString(), Toast.LENGTH_LONG).show();
if(httpResponseMsg.equalsIgnoreCase("Registration Successfully")){
finish();
Intent intent = new Intent(Activity2.this, Activity3.class);
startActivity(intent);
}
}
//REGISTRATION
@Override
protected String doInBackground(String... params) {
hashMap.put("Squadra",params[0]);
hashMap.put("Ruolo",params[1]);
hashMap.put("Numero_maglia",params[2]);
finalResult = httpParse.postRequest(hashMap, HttpURLRegister);
return finalResult;
}
}
UserRegisterFunctionClass userRegisterFunctionClass = new UserRegisterFunctionClass();
userRegisterFunctionClass.execute(Squadra, Ruolo, Numero_maglia);
}
}
总之，我无法提取'Persone'表的主键值，然后在表'Persone2'中传递外键'FK_people'中的值。 如果您知道如何传递第二个表的外键中第一个表的主键，我想知道它。 我想到了这种做法，但它不起作用。
答案 0 :(得分：0)
您在插入行之前尝试获取最后一个插入ID。所以将代码更改为类似......
if(mysqli_query($con,$Sql_Query))
{
echo 'Registration Successfully';
$People_id = mysqli_insert_id($con);
$_SESSION ['People_id'] = $People_id;
}
在两个来源中，连接在脚本末尾关闭，但只有在打开时才应关闭。两个脚本都应该移动到...的块中
if($_SERVER['REQUEST_METHOD']=='POST'){
// Rest of code...
mysqli_close($con);
}
?>