我有2个数组,我必须在同一个索引中合并数组。
Array
(
[0] => Array
(
[vendor_name] => MIRAGE PET PRODUCTS
[count_es] => 86
[outofstalk] => 19
[listing] => 64
[pricing] => 2
[discontinued] => 1
[others] => 0
)
[1] => Array
(
[vendor_name] => THE HOME DEPOT
[count_es] => 1
[outofstalk] => 0
[listing] => 1
[pricing] => 0
[discontinued] => 0
[others] => 0
)
)
这是第一个数组和
Array
( [0] => Array
(
[incorrect_esc_count] => 1
)
[1] => Array
(
[incorrect_esc_count] => 0
)
)
这是第二个数组。
我想要那个结果
Array
(
[0] => Array
(
[vendor_name] => MIRAGE PET PRODUCTS
[count_es] => 86
[outofstalk] => 19
[listing] => 64
[pricing] => 2
[discontinued] => 1
[others] => 0
[incorrect_esc_count] => 1
)
[1] => Array
(
[vendor_name] => THE HOME DEPOT
[count_es] => 1
[outofstalk] => 0
[listing] => 1
[pricing] => 0
[discontinued] => 0
[others] => 0
[incorrect_esc_count] => 0
)
)
我怎样才能实现这一目标? `第一个数组来自一个变量,第二个数组来自另一个变量。我希望这个sholud在一个数组中,因为对于视图我使用angular.js并使用表
答案 0 :(得分:0)
您正在尝试将两个多维关联数组合并为一个。这段代码应该适用于您,并提供一些注释:
<?php
// declare the first array, I did not add all of the key-value pairs
$marr1 = array
(
array("vendor_name"=>"MIRAGE PET PRODUCTS","count_es"=>86,"outofstalk"=>19),
array("vendor_name"=>"THE HOME DEPOT","count_es"=>1,"outofstalk"=>0)
);
// declare second array
$marr2 = array
(
array("incorrect_esc_count"=>1),
array("incorrect_esc_count"=>0)
);
// declare third empty array to hold the result
$marr3 = array();
// loop through both arrays
// this will not work if your arrays have different lengths
for ($i = 0; $i < count($marr1); $i++) {
// merge the ith elements of both array and then push that array into the third array
array_push($marr3, array_merge($marr1[$i],$marr2[$i]));
}
// print out result
print_r($marr3);
?>