Question

我已经在jsp和表单中开发了一个表单，如果用户点击提交按钮，那么控制器应该捕获参数，但遗憾的是它不起作用。

/*<form action="http://localhost:8080/school" method="POST">*/
<form action="/school" method="POST">
                School name: <input type="text" id="school" name="school" />
                <input type="hidden" value="${firstName}" name = "firstName"/>
                <input type="hidden" value="${lastName}" name = "lastName"/>
                <input type="submit" value="Submit" />
            </form>

控制器功能如下：

@RequestMapping(value = "/school", method = RequestMethod.POST)
    public void setSchool(HttpServletRequest request,HttpServletResponse response){
        String firstName= request.getParameter("firstName");
        String lastName= request.getParameter("lastName");
        String school= request.getParameter("school");

        String status = userController.setSchool(firstName, lastName, school);
        try {
        if(!status.equals("SUCCESS")) {

                response.sendError(HttpServletResponse.SC_FORBIDDEN, status);
        }
        response.sendRedirect("http://localhost:8080/getInsideSchool?school="+school+"&firstName="+firstName+"&lastName="+lastName);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

当我点击表格中的提交按钮时，我无法达到控制器功能。如何映射网址或修复此问题？谢谢

Answer 1

<form action="/school" method="POST">

Answer 2

首先创建一个POJO

class User {
    private String school;
    private String  firstName;
    private String  lastName;

    // getter setter constructor 
}

然后编写控制器方法如下

@RequestMapping(value = "/school", method = RequestMethod.POST)
public String home(@ModelAttribute User user) {
    System.out.println(user.toString());
    return "redirect:/home";
}

弹簧控制器中的后置方法不起作用

2 个答案: