Question

我需要这个sql来更新具有重复名称的每一行，其值为name（自动增加的数字）。例如，三行的名称如下：

name
name
name

我需要将它们更新为：

name(1)
name(2)
name(3)

代替。

我设法成功创建了一个SELECT语句。我真的在努力将其转换为实际更新。请帮忙。

我的SQL：

    SELECT id,name
      ,CASE WHEN (count(*) OVER (PARTITION BY name)) > 1 THEN
          regexp_replace(name, '(.*)',
          '\1('
          || row_number() OVER (PARTITION BY name ORDER BY id)
          || ')'
          )
       ELSE name END AS name
FROM   public.table
ORDER BY public.table.name;

我正在使用Postgres btw。

在此处发布工作解决方案：

WITH c as (
   SELECT id,name AS y
      ,CASE WHEN (count(*) OVER (PARTITION BY name)) > 1 THEN
          regexp_replace(name, '(.*)',
          '\1('
          || row_number() OVER (PARTITION BY name ORDER BY id)
          || ')'
          )
       ELSE name END AS name
FROM   public.table
ORDER BY public.table.name
)
UPDATE public.table AS t 
SET name = c.name 
FROM c
WHERE t.id = c.id
;

Answer 1

尝试update from：

with c as (
   SELECT id,name as name_o
      ,CASE WHEN (count(*) OVER (PARTITION BY name)) > 1 THEN
          regexp_replace(name, '(.*)',
          '\1('
          || row_number() OVER (PARTITION BY name ORDER BY id)
          || ')'
          )
       ELSE name END AS name
FROM   public.table
ORDER BY public.table.name
)
update public.table t 
set t.name = c.name 
from c
where t.id = c.id
;

当然在交易中 - 我无法检查声明

将此SELECT语句正确转换为更新

1 个答案: