匹配多行直到字符串包含

时间:2018-03-21 06:31:52

标签: python regex csv

我有一个包含以下信息的csv文件,我需要将正则表达式与字符串匹配为' B08-1506'起点直到下一个模式与上面的字符串匹配。我想将这三行添加为单行

B08-1506,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,
B08-1606,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,
B09-0680,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,
B09-0681,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,

输出应该是这样的,

B08-1506,324873, st, $0.0,ljkflka,jksdfhjfhjk,jkdsfh
B08-1606,324873, st, $0.0,ljkflka,jksdfhjfhjk,jkdsfh
B09-0680,324873, st, $0.0,ljkflka,jksdfhjfhjk,jkdsfh
B09-0681,324873, st, $0.0,ljkflka,jksdfhjfhjk,jkdsfh

1 个答案:

答案 0 :(得分:1)

喜欢 Nisarg 表示最好修复源csv格式。但是,如果您无法在下面的代码片段中提供帮助。

演示:没有正则表达式

s = """B08-1506,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,
B08-1606,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,
B09-0680,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,
B09-0681,324873, st, $0.0,
ljkflka,,,,,
1 of 37 jksdfhjfhjk
jkdsfh,,,,,,,"""

res = []
for i in s.split("\n"):
    if i.startswith("B0"):    #Check if line starts with "B0"
        res.append(i)
    else:                      #else concat to the previous element in res. 
        res[-1] = res[-1]+i

res = [filter(None, i.split(",")) for i in res]    #Filter to remove all empty elements
for i in res:
    print(", ".join(i))

<强>输出:

B08-1506, 324873,  st,  $0.0, ljkflka, 1 of 37 jksdfhjfhjkjkdsfh
B08-1606, 324873,  st,  $0.0, ljkflka, 1 of 37 jksdfhjfhjkjkdsfh
B09-0680, 324873,  st,  $0.0, ljkflka, 1 of 37 jksdfhjfhjkjkdsfh
B09-0681, 324873,  st,  $0.0, ljkflka, 1 of 37 jksdfhjfhjkjkdsfh