来自用户的输入是我制作的列表。现在我该如何阅读？

Question

基本上我一直试图制作这个单词生成器，它在控制台中以大字体显示你的输入。我试图获取用户的输入，然后将每个char单独放入列表中。所以现在列表中的第一项是＆＃39; a＆＃39;例如（输入为＆＃39; apple＆＃39;例如）。现在有一个名为a的列表。我想通过用户的输入（a）打印该列表。我该怎么办？这是我的代码：

a = ["@@@@@",
    ("@   @"),
    ("@   @"),
    ("@@@@@"),
    ("@   @"),
    ("@   @"),
    ("@   @")]

b = ["@@@@ ",
    ("@   @"),
    ("@   @"),
    ("@@@@ "),
    ("@   @"),
    ("@   @"),
    ("@@@@ ")]

c = ["@@@@@",
    ("@    "),
    ("@    "),
    ("@    "),
    ("@    "),
    ("@    "),
    ("@@@@@")]

d = ["@@@@ ",
    ("@   @"),
    ("@   @"),
    ("@   @"),
    ("@   @"),
    ("@   @"),
    ("@@@@ ")]

e = ["@@@@@",
    ("@    "),
    ("@    "),
    ("@@@@@"),
    ("@    "),
    ("@    "),
    ("@@@@@")]

f = ["@@@@@",
    ("@    "),
    ("@    "),
    ("@@@@@"),
    ("@    "),
    ("@    "),
    ("@    ")]

g = ["@@@@@",
    ("@    "),
    ("@    "),
    ("@ @@@"),
    ("@   @"),
    ("@   @"),
    ("@@@@@")]

h = ["@   @",
    ("@   @"),
    ("@   @"),
    ("@@@@@"),
    ("@   @"),
    ("@   @"),
    ("@   @")]

i = ["@@@@@",
    ("  @  "),
    ("  @  "),
    ("  @  "),
    ("  @  "),
    ("  @  "),
    ("@@@@@")]

j = ["    @",
    ("    @"),
    ("    @"),
    ("    @"),
    ("    @"),
    ("@   @"),
    (" @@@ ")]    

k = ["@   @",
    ("@  @ "),
    ("@ @  "),
    ("@@   "),
    ("@ @  "),
    ("@  @ "),
    ("@   @")]

l = ["@    ",
    ("@    "),
    ("@    "),
    ("@    "),
    ("@    "),
    ("@    "),
    ("@@@@@")]  

m = ["@   @",
    ("@@ @@"),
    ("@ @ @"),
    ("@ @ @"),
    ("@   @"),
    ("@   @"),
    ("@   @")]

word = []
input_word = input("Which word would you like to display?")
for i in input_word:
  word.append(i)

Answer 1

创建一个字典，将每个字母映射到相应的列表：

$.ajax({type: "POST",
    url: 'https://todoist.com/API/v6/add_item',
    dataType: 'json',
    async: false,
    data: {'token':todoist_api_token,'content': 'Appointment with Maria'}
    });

Answer 2

word包含

一词

1. 将其设为字母，其中字母为键，值为数组：letters = {'a': ["@@@@@", "@ @", "@ @", "@@@@@", "@ @", "@ @", "@ @"], ...}
2. 使用range(7) for使用for row in range(7):迭代数组中的项目数：for letter in word:
3. 迭代单词字母，获取映射的符号：outword += " " + letters[letter][row]
4. 加入空格：print('\n'.join([' '.join([{'a': ["@@@@@", "@ @", "@ @", "@@@@@", "@ @", "@ @", "@ @"] , 'b': ["@@@@ ", "@ @", "@ @", "@@@@ ", "@ @", "@ @", "@@@@ "] , 'c': ["@@@@@", "@ ", "@ ", "@ ", "@ ", "@ ", "@@@@@"] , 'd': ["@@@@ ", "@ @", "@ @", "@ @", "@ @", "@ @", "@@@@ "] , 'e': ["@@@@@", "@ ", "@ ", "@@@@@", "@ ", "@ ", "@@@@@"] , 'f': ["@@@@@", "@ ", "@ ", "@@@@@", "@ ", "@ ", "@ "] , 'g': ["@@@@@", "@ ", "@ ", "@ @@@", "@ @", "@ @", "@@@@@"] , 'h': ["@ @", "@ @", "@ @", "@@@@@", "@ @", "@ @", "@ @"] , 'i': ["@@@@@", " @ ", " @ ", " @ ", " @ ", " @ ", "@@@@@"] , 'j': [" @", " @", " @", " @", " @", "@ @", " @@@ "] , 'k': ["@ @", "@ @ ", "@ @ ", "@@ ", "@ @ ", "@ @ ", "@ @"] , 'l': ["@ ", "@ ", "@ ", "@ ", "@ ", "@ ", "@@@@@"] , 'm': ["@ @", "@@ @@", "@ @ @", "@ @ @", "@ @", "@ @", "@ @"]}[l][i] for l in "abcdefghijklm"]) for i in range(7)]))
5. 最后使用换行符加入所有行

这应该让你开始。随意尝试发布您的结果。一旦你有了一些代码，我们就可以帮到你。

1. （可选）学习列表理解，并提出一个单行程，以获得一些难以理解的乐趣

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