Question

<script type="text/javascript">
if(ytu==undefined){var ytu={q:'//img10-server.com/image/7777-88-78678678676876/robotunique-testfile.png',po:'6567567567',

我对bash / sed和其他linux脚本有点新意，我试图从上面的源代码中grep文件名“robotunique-testfile.png”，可靠而不会造成潜在的误报。

我在想也许greping "/\.png\'\,po\:/"在这个例子中足够独特。如何将此grep转换为选择文件名"robotunique-testfile.png"

Answer 1

您可以使用以下正则表达式（https://regex101.com/r/4LPNS0/1）：

# Take each frame
_, frame = cap.read(0)

# Convert BGR to HSV
hsv = cv2.cvtColor(frame, cv2.COLOR_BGR2HSV)

# define range of blue color in HSV
lower_blue = np.array([80,30,30])
upper_blue = np.array([130,150,210])

# Threshold the HSV image to get only blue colors
mask = cv2.inRange(hsv, lower_blue, upper_blue)    
# applica filtri morfologici
mask = cv2.erode(mask, spotFilter)
mask = cv2.dilate(mask, maskMorph)
# ^Now the mask is a black and white image.
# ^Get height of the black region in this image

# Bitwise-AND mask and original image
res = cv2.bitwise_and(frame,frame, mask= mask)
cv2.imshow('frame',frame)
cv2.imshow('mask',mask)
cv2.imshow('res',res)

说明：

(?<=\/)[^'\/]+(?=')

在grep中使用此正则表达式：

(?<=\/)                   Look behind for a slash
       [^'\/]+            Match anything but quote or slash 
              (?=')       Look ahead for a quote

您已经提到正则表达式应该可靠地执行并且不会导致潜在的误报。＆＃34;在这种情况下，您可以将grep -Po "(?<=\/)[^'\/]+(?=')" InputFile.txt替换为更通用的类：[^'\/]

从html源中删除文件名

1 个答案: