Question

这是我的代码示例。

PROC SQL;

CREATE TABLE SUCCESS_TIME_INTERVALS AS

SELECT

A.*,

CASE 

WHEN A.TIME BETWEEN  9:00:00 AND 11:00:00 THEN '9AM_11AM'

WHEN A.TIME BETWEEN 11:00:00 AND 13:00:00 THEN '11AM_1PM'

ELSE 'OTHER' END AS TIME_INTERVALS

FROM TABLE1 A

;QUIT;

运行代码时出现此错误

ERROR 22-322：语法错误，期待以下之一：!!，*，**，   +， - ，/，AND，||。

ERROR 76-322：语法错误，语句将被忽略。

不确定如何解决此问题。

非常感谢

Answer 1

时间常数需要单引号：

PROC SQL;
CREATE TABLE SUCCESS_TIME_INTERVALS AS
    SELECT A.*,
           (CASE WHEN A.TIME BETWEEN '09:00:00' AND '11:00:00' THEN '9AM_11AM'
                 WHEN A.TIME BETWEEN '11:00:00' AND '13:00:00' THEN '11AM_1PM'
                 ELSE 'OTHER'
            END) AS TIME_INTERVALS
    FROM TABLE1 A;
QUIT;

显然，如果time不是字符串，那么你需要恰当地表达常量：

PROC SQL;
CREATE TABLE SUCCESS_TIME_INTERVALS AS
    SELECT A.*,
           (CASE WHEN A.TIME BETWEEN '09:00:00't AND '11:00:00't THEN '9AM_11AM'
                 WHEN A.TIME BETWEEN '11:00:00't AND '13:00:00't THEN '11AM_1PM'
                 ELSE 'OTHER'
            END) AS TIME_INTERVALS
    FROM TABLE1 A;
QUIT;

用TIME构建案例陈述

1 个答案: