Ruby zip 3阵列分两步进行

时间:2018-03-14 23:31:30

标签: ruby-on-rails ruby ruby-on-rails-4

我有以下数组:

product_ids = ['id', 'id', 'id'...'id']
product_prices = ['price', 'price', 'price'...'price']

第一步我做了以下

list_1 = product_ids.zip(product_prices)

此时我有一个表单

list_1 -> [['id', 'price'],['id','price']...]

经过一些计算,我得到另一个数组

warehouses_stocks = [['stock_1', 'stock_1'..],['stock_2','stock_2'...]]

如何合并这两个(list_1和warehouses_stocks)以获取另一个格式为

的数组
[['id','price', 'stock_1', 'stock_2'],['id','price', 'stock_1', 'stock_2'],...]

1 个答案:

答案 0 :(得分:3)

product_ids = ['id_1', 'id_2']
product_prices = ['price_1', 'price_2']
warehouses_stocks = [['stock_1', 'stock_1'],['stock_2','stock_2']]

zip可以使用多个参数:

product_ids.zip(product_prices, *warehouses_stocks)
#=> [["id_1", "price_1", "stock_1", "stock_2"],
#    ["id_2", "price_2", "stock_1", "stock_2"]]