Question

我试图将userInfo从一个对象传递给一个观察视图控制器。由于某种原因，它一直在崩溃。这是代码：

观察：

NotificationCenter.default.addObserver(
        self,
        selector: #selector(self.alarmFired(_:)),
        name: Notification.Name(rawValue: "AlarmFiringNotification"),
        object: nil)

接收功能：

@objc func alarmFired(_ notification: UNNotification) {
    let userInfo = notification.request.content.userInfo
    let title = userInfo["title"] as? String
    let body = userInfo["body"] as? String
    let alert = UIAlertController(title: title, message: body, preferredStyle: .alert)
    let okAction = UIAlertAction(title: "OK", style: .default, handler: nil)
    alert.addAction(okAction)
}

通知广播：

public static func broadcastAlarmFiringNotification(with userInfo: [String: Any]) {
    NotificationCenter.default.post(Notification(name: Notification.Name(rawValue: "AlarmFiringNotification"), object: self, userInfo: userInfo))
}

广播电话：

NotificationBroadcaster.broadcastAlarmFiringNotification(with: ["title": title, "body": body])

但它一直在崩溃这个输出：

2018-03-14 18:51:06.743621-0400 App[33718:871608] -[NSConcreteNotification request]: unrecognized selector sent to instance 0x60c00005c860

2018-03-14 18:51:06.754868-0400 App[33718:871608] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[NSConcreteNotification request]: unrecognized selector sent to instance 0x60c00005c860'

它在通知广播（NotificationCenter.default.post ...）

上崩溃

我真的很困惑，感谢任何帮助！

Answer 1

UNNotification课程不是你想要的。将签名更改为：

@objc func alarmFired(notification: Notification) {
    let userInfo = notification.userInfo

Swift NotificationCenter将userInfo传递给观察视图控制器

1 个答案: