我想从19:00:00减去两个时间段16:00:00。这有什么java函数吗？结果可以是毫秒，秒或分钟。
答案 0 :(得分：106)
String time1 = "16:00:00";
String time2 = "19:00:00";
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
差异以毫秒为单位。
我修改了sfaizs post。
答案 1 :(得分：70)
Java 8有一个cleaner solution - 即时和持续时间
示例：
import java.time.Duration;
import java.time.Instant;
...
Instant start = Instant.now();
//your code
Instant end = Instant.now();
Duration timeElapsed = Duration.between(start, end);
System.out.println("Time taken: "+ timeElapsed.toMillis() +" milliseconds");
答案 2 :(得分：34)
为了得到漂亮的时间差异，那么
// d1, d2 are dates
long diff = d2.getTime() - d1.getTime();
long diffSeconds = diff / 1000 % 60;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
System.out.print(diffDays + " days, ");
System.out.print(diffHours + " hours, ");
System.out.print(diffMinutes + " minutes, ");
System.out.print(diffSeconds + " seconds.");
答案 3 :(得分：30)
Java 8
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss");
LocalDateTime dateTime1= LocalDateTime.parse("2014-11-25 19:00:00", formatter);
LocalDateTime dateTime2= LocalDateTime.parse("2014-11-25 16:00:00", formatter);
long diffInMilli = java.time.Duration.between(dateTime1, dateTime2).toMillis();
long diffInSeconds = java.time.Duration.between(dateTime1, dateTime2).getSeconds();
long diffInMinutes = java.time.Duration.between(dateTime1, dateTime2).toMinutes();
答案 4 :(得分：11)
就像任何其他语言一样;将你的时间段转换为unix时间戳（即自Unix纪元以来的秒数），然后简单地减去。 然后，生成的秒应该用作新的unix时间戳，并以您想要的任何格式读取格式。
啊，给上面的海报（geneiss）他应有的信用，代码总是很方便;） 虽然，你现在也有一个解释：）
答案 5 :(得分：7)
import java.util.Date;
...
Date d1 = new Date();
...
...
Date d2 = new Date();
System.out.println(d2.getTime()-d1.getTime()); //gives the time difference in milliseconds.
System.out.println((d2.getTime()-d1.getTime())/1000); //gives the time difference in seconds.
并且，为了以更好的格式显示，您可以使用：
DecimalFormat myDecimalFormatter = new DecimalFormat("###,###.###");
System.out.println(myDecimalFormatter.format(((double)d2.getTime()-d1.getTime())/1000));
答案 6 :(得分：2)
痛苦的方法是转换为毫秒并进行减法，然后回到你想要的任何秒数。更好的方法是使用JodaTime。
答案 7 :(得分：1)
如果采取不同日期的时间，则选择其他选项，例如：22：00和01:55。
public static long getDiffTime(Date date1, Date date2){
if (date2.getTime() - date1.getTime() < 0) {// if for example date1 = 22:00, date2 = 01:55.
Calendar c = Calendar.getInstance();
c.setTime(date2);
c.add(Calendar.DATE, 1);
date2 = c.getTime();
} //else for example date1 = 01:55, date2 = 03:55.
long ms = date2.getTime() - date1.getTime();
//235 minutes ~ 4 hours for (22:00 -- 01:55).
//120 minutes ~ 2 hours for (01:55 -- 03:55).
return TimeUnit.MINUTES.convert(ms, TimeUnit.MILLISECONDS);
}
答案 8 :(得分：1)
String start = "12:00:00";
String end = "02:05:00";
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(start);
Date date2 = format.parse(end);
long difference = date2.getTime() - date1.getTime();
int minutes = (int) TimeUnit.MILLISECONDS.toMinutes(difference);
if(minutes<0)minutes += 1440;
现在分钟将是两次（以分钟为单位）之间的正确持续时间。
答案 9 :(得分：1)
import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String[] args) throws Exception{
String time1 = "12:00:00";
String time2 = "12:01:00";
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
System.out.println(difference/1000);
}}
抛出异常句柄解析异常
答案 10 :(得分：0)
这可以使用 Java 8 LocalTime 轻松完成；
String time1 = "16:00:00";
String time2 = "19:00:00";
long seconds = Duration.between(LocalTime.parse(time1), LocalTime.parse(time2)).getSeconds()
Duration 还支持 toMillis()、toMinutes()，可以代替 getSeconds() 来获取毫秒或分钟
答案 11 :(得分：0)
我发现它更干净。
Date start = new Date();
//Waiting for 10 seconds
Thread.sleep(10000);
Date end = new Date();
long diff = end.getTime() - start.getTime();
String TimeTaken = String.format("[%s] hours : [%s] mins : [%s] secs",
Long.toString(TimeUnit.MILLISECONDS.toHours(diff)),
TimeUnit.MILLISECONDS.toMinutes(diff),
TimeUnit.MILLISECONDS.toSeconds(diff));
System.out.println(String.format("Time taken %s", TimeTaken));
输出：花费的时间[0]小时：[0]分钟：[10]秒
答案 12 :(得分：0)
import java.sql.*;
class Time3 {
public static void main(String args[]){
String time1 = "01:03:23";
String time2 = "02:32:00";
long difference ;
Time t1 = Time.valueOf(time1);
Time t2 = Time.valueOf(time2);
if(t2.getTime() >= t1.getTime()){
difference = t2.getTime() - t1.getTime() -19800000;
}
else{
difference = t1.getTime() - t2.getTime() -19800000;
}
java.sql.Time time = new java.sql.Time(difference);
System.out.println(time);
}
}
答案 13 :(得分：0)
除了最常见的使用Period和Duration对象的方法之外，您还可以使用Java处理时间的另一种方式来扩展知识。
高级Java 8库。 ChronoUnit （差异）。
ChronoUnit是确定两个时间值相隔多远的好方法。时态包括 LocalDate ， LocalTime 等。
LocalTime one = LocalTime.of(5,15);
LocalTime two = LocalTime.of(6,30);
LocalDate date = LocalDate.of(2019, 1, 29);
System.out.println(ChronoUnit.HOURS.between(one, two)); //1
System.out.println(ChronoUnit.MINUTES.between(one, two)); //75
System.out.println(ChronoUnit.MINUTES.between(one, date)); //DateTimeException
第一个示例显示了在截断之间而不是在舍入之间。
第二个显示了对不同单位进行计数是多么容易。
最后一个例子提醒我们，我们不应该弄乱Java中的日期和时间：）
答案 14 :(得分：0)
public class timeDifference {
public static void main(String[] args) {
try {
Date startTime = Calendar.getInstance().getTime();
Thread.sleep(10000);
Date endTime = Calendar.getInstance().getTime();
long difference = endTime.getTime() - startTime.getTime();
long differenceSeconds = difference / 1000 % 60;
long differenceMinutes = difference / (60 * 1000) % 60;
long differenceHours = difference / (60 * 60 * 1000) % 24;
long differenceDays = difference / (24 * 60 * 60 * 1000);
System.out.println(differenceDays + " days, ");
System.out.println(differenceHours + " hours, ");
System.out.println(differenceMinutes + " minutes, ");
System.out.println(differenceSeconds + " seconds.");
} catch (Exception e) {
e.printStackTrace();
}
}
}
答案 15 :(得分：0)
类TimeCalculator { String updateTime;
public TimeCalculator(String time)
{
// time should be in 24 hours format like 15/06/2016 17:39:20
this.updateTime = time;
}
public String getTimeDifference()
{
String td=null;
// get Current Time
SimpleDateFormat sdf = new SimpleDateFormat("dd/MM/yyyy hh:mm:ss");
Date currentDate = new Date();
Calendar calendar = new GregorianCalendar();
calendar.setTime(currentDate);
int c_year = calendar.get(Calendar.YEAR);
int c_month = calendar.get(Calendar.MONTH) + 1;
int c_day = calendar.get(Calendar.DAY_OF_MONTH);
// get Editing Time
Date edit_date = sdf.parse(updateTime);
Calendar edit_calendar = new GregorianCalendar();
edit_calendar.setTime(edit_date);
int e_year = edit_calendar.get(Calendar.YEAR);
int e_month = edit_calendar.get(Calendar.MONTH) + 1;
int e_day = edit_calendar.get(Calendar.DAY_OF_MONTH);
if(e_year==c_year&&e_month==c_month&&e_day==c_day)
{
int c_hours = calendar.get(Calendar.HOUR_OF_DAY);
int c_minutes = calendar.get(Calendar.MINUTE);
int c_seconds = calendar.get(Calendar.SECOND);
int e_hours = edit_calendar.get(Calendar.HOUR_OF_DAY);
int e_minutes = edit_calendar.get(Calendar.MINUTE);
int e_seconds = edit_calendar.get(Calendar.SECOND);
if(c_hours==e_hours&&c_minutes==e_minutes&&c_seconds==e_seconds)
{
td = "just now";
return td;
}
else if(c_hours==e_hours&&c_minutes==e_minutes)
{
int d_seconds = c_seconds-e_seconds;
td = String.valueOf(d_seconds);
td = td+" seconds ago";
return td;
}
else if(c_hours==e_hours&&c_minutes!=e_minutes)
{
int d_minutes = c_minutes-e_minutes;
int d_seconds;
if(c_seconds>e_seconds)
{
d_seconds = c_seconds-e_seconds;
}else{
d_seconds = e_seconds-c_seconds;
}
td = "00:"+String.valueOf(d_minutes)+":"+String.valueOf(d_seconds)+" ago";
return td;
}
else
{
int d_minutes,d_seconds,d_hours;
d_hours=c_hours-e_hours;
if(c_minutes>e_minutes)
{
d_minutes = c_minutes-e_minutes;
}else{
d_minutes = e_minutes-c_minutes;
}
if(c_seconds>e_seconds)
{
d_seconds = c_seconds-e_seconds;
}else{
d_seconds = e_seconds-c_seconds;
}
td = String.valueOf(d_hours)+":"+String.valueOf(d_minutes)+":"+String.valueOf(d_seconds)+" ago";
return td;
}
}
else if(e_year==c_year&&e_month==c_month&&c_day==e_day+1){
td = "yesterday";
return td;
}
else{
td = updateTime;
return td;
}
}}
答案 16 :(得分：0)
/*
* Total time calculation.
*/
private void getTotalHours() {
try {
// TODO Auto-generated method stub
if (tfTimeIn.getValue() != null && tfTimeOut.getValue() != null) {
Long min1 = tfTimeOut.getMinutesValue();
Long min2 = tfTimeIn.getMinutesValue();
Long hr1 = tfTimeOut.getHoursValue();
Long hr2 = tfTimeIn.getHoursValue();
Long hrsTotal = new Long("0");
Long minTotal = new Long("0");
if ((hr2 - hr1) == 1) {
hrsTotal = (long) 1;
if (min1 != 0 && min2 == 0) {
minTotal = (long) 60 - min1;
} else if (min1 == 0 && min2 != 0) {
minTotal = min2;
} else if (min1 != 0 && min2 != 0) {
minTotal = min2;
Long minOne = (long) 60 - min1;
Long minTwo = min2;
minTotal = minOne + minTwo;
}
if (minTotal >= 60) {
hrsTotal++;
minTotal = minTotal % 60;
}
} else if ((hr2 - hr1) > 0) {
hrsTotal = (hr2 - hr1);
if (min1 != 0 && min2 == 0) {
minTotal = (long) 60 - min1;
} else if (min1 == 0 && min2 != 0) {
minTotal = min2;
} else if (min1 != 0 && min2 != 0) {
minTotal = min2;
Long minOne = (long) 60 - min1;
Long minTwo = min2;
minTotal = minOne + minTwo;
}
if (minTotal >= 60) {
minTotal = minTotal % 60;
}
} else if ((hr2 - hr1) == 0) {
if (min1 != 0 || min2 != 0) {
if (min2 > min1) {
hrsTotal = (long) 0;
minTotal = min2 - min1;
} else {
Notification.show("Enter A Valid Time");
tfTotalTime.setValue("00.00");
}
}
} else {
Notification.show("Enter A Valid Time");
tfTotalTime.setValue("00.00");
}
String hrsTotalString = hrsTotal.toString();
String minTotalString = minTotal.toString();
if (hrsTotalString.trim().length() == 1) {
hrsTotalString = "0" + hrsTotalString;
}
if (minTotalString.trim().length() == 1) {
minTotalString = "0" + minTotalString;
}
tfTotalTime.setValue(hrsTotalString + ":" + minTotalString);
} else {
tfTotalTime.setValue("00.00");
}
}
catch (Exception e) {
e.printStackTrace();
}
}
答案 17 :(得分：-1)
尝试一下：
public String timeDifference8(String startTime, String endTime) {
LocalTime initialTime = LocalTime.parse(startTime);
LocalTime finalTime =LocalTime.parse(endTime);
StringJoiner joiner = new StringJoiner(":");
long hours = initialTime.until( finalTime, ChronoUnit.HOURS);
initialTime = initialTime.plusHours( hours );
long minutes = initialTime.until(finalTime, ChronoUnit.MINUTES);
initialTime = initialTime.plusMinutes( minutes );
long seconds = initialTime.until( finalTime, ChronoUnit.SECONDS);
joiner.add(String.valueOf(hours));
joiner.add(String.valueOf(minutes));
joiner.add(String.valueOf(seconds));
return joiner.toString();
}