Question

我正在尝试删除数组中项目的前7个字符，更具体地说，我试图删除“mailto”，以便它只显示电子邮件

我认为使用[：7]可以解决这个问题，但python忽略了请求。

有什么建议吗？

def businessprofile(self, response):
    for business in response.css('header#main-header'):
        item = Item()
        item['business_name'] = business.css('div.sales-info h1::text').extract()
        item['website'] = business.css('a.secondary-btn.website-link::attr(href)').extract()
        # i want to remove the first 7 characters "mailto:", but not sure how ? i made an attempt
        item['email'] = business.css('a.email-business::attr(href)').extract()[7:]
        item['phonenumber'] = business.css('p.phone::text').extract_first()
        for x in item['business_name']:
            #new code here, call to self.seen_business_names
            if x not in self.seen_business_names:
                if item['business_name']:
                    if item['phonenumber']:
                        if item['email']:                               
                            yield item
                            self.seen_business_names.append(x)

这是我需要删除字符的地方

   item['email'] = business.css('a.email-business::attr(href)').extract()[7:]

Answer 1

显然business.css('a.email-business::attr(href)').extract()会返回一个列表。您需要从列表中的项目中删除mailto:。

s = business.css('a.email-business::attr(href)').extract()
item['email'] = [item[7:] for item in s]
# ['businessname@gmail.com']

或者

s = business.css('a.email-business::attr(href)').extract()
item['email'] = [item.replace('mailto:', '') for item in s]
# ['businessname@gmail.com']

Answer 2

您需要使用[7:]而不是[:7]

语法为[<start>:<end>]，省略时会自动从字符串的开头或结尾开始。

例如：

val = "mailto:abc@abc.de"
mailto = val[:7] # from first charater to 7th = 'mailto:'
email = val[7:] # 8th character to the end.

Answer 3

计数从0开始：

a = "0123456789"
a[7:]
# '789'

所以你可能需要

a[8:]
# '89'

如何在python scrapy中删除数组中项的第一个字符

3 个答案: