Question

当我将字符串元组创建为元组 的元素时，它可以正常工作，但是当我创建字符串元组作为<的元素时，它不起作用Python 3中的strong>字典 。

Python shell状态如下：

    =============================== RESTART: Shell ===============================
>>> keys = ("one","two","three")
>>> 
>>> TD1 = [["\0" for x in range(2)] for y in range(3)]
>>> TD1[0] = ("First","Tuple")
>>> TD1
[('First', 'Tuple'), ['\x00', '\x00'], ['\x00', '\x00']] 
>>> #string tuples as an element of a tuple created
>>> 
>>> TD2 = [["\0" for x in range(2)] for y in keys]
>>> TD2["one"] = ("First","Tuple")
Traceback (most recent call last):
  File "<pyshell#35>", line 1, in <module>
    TD2["one"] = ("First","Tuple")
TypeError: list indices must be integers or slices, not str
>>> #string tuples as an element of a dictionary not created
>>>

有人可以告诉我怎么做...我想创建字符串元组作为字典的元素。我想要一个像这样引用相同名称的结构：

＆＃34;颜色＆＃34; =（＆＃34; Red＆＃34;，＆＃34; Blue＆＃34;，＆＃34; Green＆＃34;，＆＃34; Yellow＆＃34;，＆＃34; Pink＆＃34;）

＆＃34;动物＆＃34; =（＆＃34; Lion＆＃34;，＆＃34; Horse＆＃34;，＆＃34; Kangaroo＆＃34;，＆＃34; Dog＆＃34;，＆＃34; Bull＆＃34;）

＆＃34;鸟＆＃34; =（＆＃34; Parrot＆＃34;，＆＃34;夜莺＆＃34;，＆＃34; Hawk＆＃34;，＆＃34; Sparrow＆＃34;，＆＃34; Eagle＆＃34;）

＆＃34;水果＆＃34; =（＆＃34; Mango＆＃34;，＆＃34; Apple＆＃34;，＆＃34; Cherry＆＃34;，＆＃34; Grapes＆＃34;，＆＃34; Banana＆＃34;）

Answer 1

这里的问题是TD2是一个列表，而不是字典。如果你想获得一本字典，你可以使用dict comprehension：

 TD2 = {y: ["\0" for x in range(2)] for y in keys}

注意大括号和key: value表达式。

Answer 2

这是代码但有效。你需要使字典成为字典。你的TD2是一个清单。

{
  "message":{
     "token":"bk3RNwTe3H0:CI2k_HHwgIpoDKCIZvvDMExUdFQ3P1...",
     "notification":{
       "title":"Match update",
       "body":"Arsenal goal in added time, score is now 3-0"
     },
     "android":{
       "ttl":"86400s",
       "notification"{
         "click_action":"OPEN_ACTIVITY_1"
       }
     },
     "apns": {
       "headers": {
         "apns-priority": "5",
       },
       "payload": {
         "aps": {
           "category": "NEW_MESSAGE_CATEGORY"
         }
       }
     },
     "webpush":{
       "headers":{
         "TTL":"86400"
       }
     }
   }
 }

在Python 3中将元组创建为字典元素时，它表示元素必须是int或slice

2 个答案: