Question

网址的JSON格式不符合标准格式：

{}&& {identifier:'ID', label:'As at 08-03-2018 5:06 PM',items:[{ID:0,N:'2ndChance W200123',SIP:'',NC:'CDWW',R:'',I:'',M:'',LT:0.009,C:0.000,VL:108.200,BV:2149.900,B:'0.008',S:'0.009',SV:7218.300,O:0.009,H:0.009,L:0.008,V:873.700,SC:'5',PV:0.009,P:0.000,BL:'100',P_:'X',V_:''},{ID:1,N:'3Cnergy',SIP:'',NC:'502',R:'',I:'',M:'t',LT:0,C:0,VL:0.000,BV:50.000,B:'0.022',S:'0.025',SV:36.000,O:0,H:0,L:0,V:0.000,SC:'2',PV:0.021,P:0,BL:'100',P_:'X',V_:''},{ID:2,N:'3Cnergy W200528',SIP:'',NC:'1E0W',R:'',I:'',M:'t',LT:0,C:0,VL:0.000,BV:0,B:'',S:'0.004',SV:50.000,O:0,H:0,L:0,V:0.000,SC:'5',PV:0.002,P:0,BL:'100',P_:'X',V_:''}`

我想将所有数据放入列表或从ID开始的pandas中。

我请求网址时不需要

{}&& {identifier:'ID', label:'As at 08-03-2018 5:06 PM',items:

headers = {'User-Agent': 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_11_5) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/50.0.2661.102 Safari/537.36'}
url ='AttributeError: 'http://www.sgx.com/JsonRead/JsonstData?qryId=RAll'
page = requests.get(url,headers=headers)
alldata = html.fromstring(page.content)

但是，我无法继续，因为JSON格式不是标准格式。怎么纠正呢？

Answer 1

$ sudo curl -L https://toolbelt.treasuredata.com/sh/install-redhat-td-agent2.sh | sh

数据为JavaScript Object, in literal notation。我们可以使用PyExecJs来评估它并得到相应的python dict。

Python：将不需要的数据删除到标准json

1 个答案: