jQuery Flot清晰选择

Question

好的，我很确定一旦我开始使用Flot，演示页面上的“清除选择”按钮就可以工作，http://people.iola.dk/olau/flot/examples/selection.html。它对你们任何人都有效吗？我试过IE 7/8和Firefox。

当我尝试在我的图表中实现相同的功能并且无法使其工作时，我才注意到这一点，只是为了找到不在演示页面上工作的示例......

这是我的代码：

$.post(applicationPath + "graph/" + action,
    function (data)
    {
        var graphOptions = {
            xaxis: {
                mode: 'time',
                timeformat: "%m/%d/%y"
            },
            yaxis: {
                tickDecimals: 0
            },
            legend: {
                show: true,
                container: $('.legend')
            },
            series: {
                points: { show: true },
                lines: { show: true }
            },
            grid: {
                hoverable: true,
                clickable: true
            },
            selection: {
                mode: "xy"
            }
        };

        // hard-code color indices to prevent them from shifting as
        // series are turned on/off
        var i = 0;
        $.each(data, function (key, val)
        {
            val.color = i;
            i++;
        });

        var optionsContainer = $('.module.graph .options-menu');

        $.each(data, function (key, val)
        {
            optionsContainer.append('<li><input type="checkbox" name="' + key + '" checked="checked" id="id' + key + '">' + val.label + '</li>');
        });

        $('.module.graph .header .options').optionsMenu(
        {
            sTarget: '.options-menu',
            fnCheckboxSelected: function (index, name)
            {
                $.plot(data, optionsContainer, graphOptions);
            },
            fnCheckboxDeselected: function (index, name)
            {
                $.plot(data, optionsContainer, graphOptions);
            }
        });

        var dataSet = [];

        optionsContainer.find('input:checked').each(function ()
        {
            var key = $(this).attr('name');

            if (key && data[key])
            {
                dataSet.push(data[key]);
            }
        });

        var previousPoint = null;
        var graphContainer = $('.graph #graph-container');

        graphContainer.bind('plothover', function (e, pos, item, ranges)
        {
            if (item)
            {
                if (previousPoint != item.datapoint)
                {
                    previousPoint = item.datapoint;

                    $('#tooltip').remove();

                    var xFormatted = new Date(item.datapoint[0]).toDateString();
                    var x = item.datapoint[0].toFixed(2);
                    var y = item.datapoint[1].toFixed(2);

                    showGraphToolTip(item.pageX, item.pageY, item.series.label + " of " + y + " on " + xFormatted);
                }
            }
            else
            {
                $('#tooltip').remove();
                previousPoint = null;
            }
        });

        graphContainer.bind('plotselected', function (event, ranges)
        {
            if (ranges.xaxis.to - ranges.xaxis.from < 0.00001)
            {
                ranges.xaxis.to = ranges.xaxis.from + 0.00001;
            }
            if (ranges.yaxis.to - ranges.yaxis.from < 0.00001)
            {
                ranges.yaxis.to = ranges.yaxis.from + 0.00001;
            }

            $.plot(graphContainer, dataSet,

                $.extend(true, {}, graphOptions,
                {
                    xaxis: { min: ranges.xaxis.from, max: ranges.xaxis.to },
                    yaxis: { min: ranges.yaxis.from, max: ranges.yaxis.to }
                })
            );
        });

        var graph = $.plot(graphContainer, dataSet, graphOptions);

        $('#clearSelection').click(function ()
        {
            graph.clearSelection();
        });
    },
    "json"
);

我真的看不出我的代码有什么问题，因为它实际上是Flot示例的副本和过去，但这里有什么明显的东西吗？

此外，Flot中是否存在可能的错误？明确的选择演示是否适合您？

Answer 1

来自flot.googlecode.com

  

  
• setupGrid（）
  

Recalculate and set axis scaling, ticks, legend etc.

Note that because of the drawing model of the canvas, this
function will immediately redraw (actually reinsert in the DOM)
the labels and the legend, but not the actual tick lines because
they're drawn on the canvas. You need to call draw() to get the
canvas redrawn.

如果将其添加到重置功能，您应该能够按预期工作。